Javascript数组:如何删除包含在另一个数组中的所有匹配元素

const array1 = [1, 2, 3, 4, 5];
const array2 = [2, 4];

const filteredArray = array1.filter(element => !array2.includes(element));

console.log(filteredArray); // 输出 [1, 3, 5]

const array1 = [1, 2, 3, 4, 5];
const array2 = [2, 4];

array2.forEach(element => {
  const index = array1.indexOf(element);
  if (index !== -1) {
    array1.splice(index, 1);
  }
});

console.log(array1); // 输出 [1, 3, 5]

const array1 = [1, 2, 3, 4, 5];
const array2 = [2, 4];

const filteredArray = array1.reduce((accumulator, element) => {
  if (!array2.includes(element)) {
    accumulator.push(element);
  }
  return accumulator;
}, []);

console.log(filteredArray); // 输出 [1, 3, 5]