Laravel -如何根据所选的单选按钮有条件地显示输入选择框？

<input type="radio" name="option" value="option1"> Option 1
<input type="radio" name="option" value="option2"> Option 2

$(document).ready(function() {
    $('input[name="option"]').change(function() {
        var selectedOption = $(this).val();
        
        if (selectedOption === 'option1') {
            $('#input1').show();
            $('#input2').hide();
        } else if (selectedOption === 'option2') {
            $('#input1').hide();
            $('#input2').show();
        }
    });
});

<div id="input1" style="display: none;">
    <input type="text" name="input1" placeholder="Input 1">
</div>

<div id="input2" style="display: none;">
    <input type="text" name="input2" placeholder="Input 2">
</div>