PHP MySQL:如何从MySQL表中检索与项目id相关联的所有图像

$servername = "数据库服务器地址";
$username = "数据库用户名";
$password = "数据库密码";
$dbname = "数据库名称";

// 使用mysqli扩展连接到MySQL数据库
$conn = new mysqli($servername, $username, $password, $dbname);
if ($conn->connect_error) {
    die("连接失败: " . $conn->connect_error);
}

// 使用PDO扩展连接到MySQL数据库
try {
    $conn = new PDO("mysql:host=$servername;dbname=$dbname", $username, $password);
    $conn->setAttribute(PDO::ATTR_ERRMODE, PDO::ERRMODE_EXCEPTION);
} catch(PDOException $e) {
    die("连接失败: " . $e->getMessage());
}

$project_id = 1; // 项目id

// 使用mysqli扩展执行MySQL查询
$sql = "SELECT * FROM images WHERE project_id = $project_id";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
    while($row = $result->fetch_assoc()) {
        // 处理每个图像的数据
        $image_id = $row["id"];
        $image_url = $row["url"];
        // 其他操作...
    }
} else {
    echo "没有找到相关图像";
}

// 使用PDO扩展执行MySQL查询
$sql = "SELECT * FROM images WHERE project_id = :project_id";
$stmt = $conn->prepare($sql);
$stmt->bindParam(':project_id', $project_id);
$stmt->execute();

if ($stmt->rowCount() > 0) {
    while($row = $stmt->fetch(PDO::FETCH_ASSOC)) {
        // 处理每个图像的数据
        $image_id = $row["id"];
        $image_url = $row["url"];
        // 其他操作...
    }
} else {
    echo "没有找到相关图像";
}