Python:给定两个文件名列表，根据日期部分找到常见的文件名

import datetime

def find_common_filenames(filenames1, filenames2):
    common_filenames = []
    
    for filename1 in filenames1:
        date1 = extract_date(filename1)
        
        for filename2 in filenames2:
            date2 = extract_date(filename2)
            
            if date1 == date2:
                common_filenames.append(filename1)
                break
    
    return common_filenames

def extract_date(filename):
    # 根据文件名格式提取日期部分，这里假设日期部分在文件名的前8个字符
    date_str = filename[:8]
    
    # 将日期字符串转换为日期对象
    date = datetime.datetime.strptime(date_str, '%Y%m%d').date()
    
    return date

# 示例用法
filenames1 = ['20220101_file1.txt', '20220102_file2.txt', '20220103_file3.txt']
filenames2 = ['20220102_file4.txt', '20220103_file5.txt', '20220104_file6.txt']

common_filenames = find_common_filenames(filenames1, filenames2)
print(common_filenames)