null},
{id: 4, Name: '女装', pId: 1, state: 1, remark: null},
{id: 5, Name: '裤子', pId: 1, state: 1, remark...: null},
{id: 6, Name: '连衣裙', pId: 4, state: 1, remark: null},
{id: 7, Name: '雪纺衫', pId: 4, state: 1,...remark: null},
{id: 8, Name: '短裤', pId: 5, state: 1, remark: null},
{id: 9, Name: '衬衫', pId: 3, state...children)
map.get(pid).children = [];
var obj = new Object(data[i]);
map.get(pid).children.push...(键名和键值)给它删掉
delete o[RelationObj[key as keyof typeof RelationObj]];
// 新对象的键名对应的值等于老对象的键名