__init__() takes 1 positional argument but 2 were given_typeerror: __init__() takes 1 positional argument but 2 were given - 腾讯云开发者社区

): File "test.py", line 5, in <module c = fun(1, 2, 3) TypeError: fun() takes 2 positional arguments...but 3 were given ``` 上面的代码中， fun 函数定义了两个必须参数，但在调用 fun 函数时，传入了 3 个参数，导致了报错。...```python def addTwoNums(a, b): return a + b num1 = 1 num2 = 2 result = addTwoNums(num1, num2) print...```python def isOdd(num): return num % 2 == 1 print(isOdd(1)) print(isOdd(2)) print(isOdd(3)) ```...```python def isEven(num): return num % 2 == 0 print(isEven(1)) print(isEven(2)) print(isEven(3))

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xadmin+django2.0删除用户报错，get_deleted_objects() takes 3 positional arguments but 5 were given

解决方法：将xadmin/plugins/actions.py中的 if django_version > (2, 0): #deletable_objects,...queryset, self.opts, self.user, self.admin_site, using) 改为 if django_version > (2,...1): deletable_objects, model_count, perms_needed, protected = get_deleted_objects(

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Python Django开发异常及其解决办法（一）

__() takes 1 positional argument but 6 were given 8.Django xadmin数据迁移ImportError 9.Django xadmin数据迁移AttributeError...2.NoReverseMatch: Reverse for ‘xxx’ not found ....7.Django xadmin数据迁移__init__() takes 1 positional argument but 6 were given 在安装xadmin后进行数据迁移时，报错： forms.Field...__init__(self, required, widget, label, initial, help_text, TypeError: __init__() takes 1 positional...argument but 6 were given 直接找到xadmin\views\dashboard.py，将forms.Field.

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Django在根据models生成数据库表时报 init() missing 1 required positional argument on_d

File "E:\diango\blog\models.py", line 25, in Entry blog = models.ForeignKey(Blog) TypeError: __init...__() missing 1 required positional argument: 'on_delete' 解决办法：将有ForeignKey的代码改为： blog = models.ForeignKey

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xadmin 因为版本问题的错误

NoReverseMatch, reverse 改成 from django.urls import NoReverseMatch, reverse 2....TypeError: __init__() missing 1 required positional argument: 'on_delete' 解决方法：将user = models.ForeignKey...u"user")， on_delete=models.CASCADE) 即在外键值的后面加上 on_delete=models.CASCADE 3.TypeError: __init...__() takes 1 positional argument but 6 were given 解决方法：将forms.Field....'django.contrib.sessions.middleware.SessionMiddleware', 2 'django.middleware.common.CommonMiddleware

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Python–socketserve源码分析(一)

_": a = A(1,2) >>>> 1,2 情况2： #coding:UTF-8 class Base: def __init__(self): self.ip =..., b): print (a,b) class A(Base, B): pass if __name__ == "__main__": a = A(1,2...) >>>> Traceback (most recent call last): >>>> File “test.py”, line 20, in >>>> a = A(1,2) >...>>> TypeError: __init__() takes 1 positional argument but 3 were given 情况3： #coding:UTF-8 class Base...(a,b) class A(Base, B): pass if __name__ == "__main__": a = A(1,2) >>>> Base fun 发布者

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paddleNLP-BUG和一些细节记录【一】

1.TypeError: isfile() takes 1 positional argument but 2 were given File "/root/miniconda3/envs/paddle_nlp...tokenizer_utils_base.py", line 1623, in from_pretrained '') and os.path.isfile(file_path): TypeError: isfile() takes...1 positional argument but 2 were given 把源码这个位置的 '' 参数删掉就可以了 2.

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Django项目中xadmin遇到的坑记录

第一次写Django项目，使用xadmin报了一大堆的错误，此次记录一下问题和方法方便下次使用 xadmin下载：在百度中搜索GitHub，进入官网，然后搜索xadmin即可 image.png 1、...django.core.urlresolvers 　　更改为了 django.urls 3、错误提示：ImportError: cannot import name ‘six‘ from ‘django.utils‘ 解决方法：　　1...._2_unicode_compatible 5、错误提示：TypeError: __init__() takes 1 positional argument but 6 were given 解决方法...import logout 　　修改为 from django.contrib.auth.views import LogoutView as logout 8、错误提示：TypeError: __init...__() missing 1 required positional argument: 'on_delete' 解决方法：　　关联关系ForeignKey引发的错误，凡是出现关联关系字段的地方全部加上

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Python学习笔记（二）

(most recent call last): File "", line 1, in TypeError: function1() takes 2 positional...arguments but 3 were given >>> 如果在定义函数时，参数的末尾有一个指定的参数值时，那么这个参数就是默认参数，即在传参时不写相对应的参数值时，默认将使用预先定义好的数值。..."", line 1, in TypeError: function4() takes 1 positional argument but 3 were given >...>", line 1, in TypeError: function5() takes 1 positional argument but 2 were given >>> function5..., line 1 SyntaxError: positional argument follows keyword argument >>> return: 在函数最后加上return 可以指定函数执行完后想要返回的一个值

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Point(类与构造) Python

输入测试数据的组数 t 第一组测试数据点p1的x坐标第一组测试数据点p1的y坐标第一组测试数据点p2的x坐标第一组测试数据点p2的y坐标 .............1 2 3 4 -1 0.5 -2 5 输出样例1 Distance of Point(1.00,2.00) to Point(3.00,4.00) is 2.83 Distance of Point...__init__() takes 1 positional argument but 3 were given 去网上搜了一下，发现是__init__写成了__int__ …… AC代码 import...(self.y-p.y)**2) test=int(input()) for i in range(0,test): x1,y1,x2,y2=map(float,input().split())...a,b=Point(x1,y1),Point(x2,y2) print('Distance of Point(%.2f,%.2f)to Point(%.2f,%.2f)is %.2f'

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Python @staticmethod和@classmethod

Math.mod_classmethod(10, 30)) 26 print(Math.mod_staticmethod(10, 30)) TypeError: mod_classmethod() takes...2 positional arguments but 3 were given ------------------------------------------------------------...required positional argument: 'y' test None -------------------------------------------------------...print(Math.test_staticmethod()) ---> 10 print(Math.test_classmethod()) TypeError: test_classmethod() takes...0 positional arguments but 1 was given 本例说明了@staicmethod和@classmethod的异同点以及self和cls的异同点：都可以实现将方法定义为类的方法

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Python - 3.8 新特性之仅位置参数 & 仅关键字参数

test(1, b=2, c=3) test(*(1,), b=2, c=3) # 错误 test(a=1, b=2, c=3) 1 2 3 1 2 3 1 2 3 test(a=1,...b=2, c=3) TypeError: test() got some positional-only arguments passed as keyword arguments: 'a' 报错信息...a, *, b, c): return a + b + c # 正确 f1(1, b=2, c=3) f1(1, **{"b": 2, "c": 3}) # 错误 f1(1, 2, c=3...) # 输出结果 6 6 f1(1, 2, c=3) TypeError: f1() takes 1 positional argument but 2 positional arguments...(and 1 keyword-only argument) were given 报错信息：接受1个位置参数，但提供了2个位置参数（和1个仅限关键字的参数）在 * 形参后的参数只能通过关键字参数传递

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Python 中的默认值是什么？

positional argument(website) # here it takes the given default values for author(XYZ) and language(Python...('tutorialspoint', 'Alex', 'Java') # calling 2 positional arguments (website, author) # here it takes...takes the given default value for author(XYZ) tutorialspoint('tutorialspoint', 'C++') 输出在执行时，上述程序将生成以下输出...positional argument(website) with keywords # here it takes the given default values for author(XYZ) and...language(Python) tutorialspoint(website= 'tutorialspoint') # calling 2 positional arguments (website

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Python函数中单独一个星号或斜线作为形参的含义

>>> def demo(a, b, *, c):#参数c必须以关键参数进行传值 print(a+b+c) >>> demo(1, 2, c=3) #正确 6 >>> demo(1, 2, 3) #错误...，引发异常 TypeError: demo() takes 2 positional arguments but 3 were given >>> def demo(a, b, *p, c):#参数c必须以关键参数进行传值...print(a+b+c+sum(p)) >>> demo(1, 2, 3, 4, c=5) #正确 15 >>> demo(1, 2, 3, 4, 5) #错误，引发异常 TypeError: demo...() missing 1 required keyword-only argument: 'c' 另外如果用help()函数查看sum()函数的帮助文档时，会发现sum()函数的最后一个参数是斜线，实际上这个斜线并不是...2, 3], 4) #按位置参数对start进行传值 10 >>> sum([1, 2, 3], start=4)#不允许使用关键参数，引发异常 TypeError: sum() takes no keyword

3.1K6 0

Python函数参数和注解是什么

func("dongfanger", j="1", k="2") dongfanger () Hello World {'j': '1', 'k': '2'} ④second只能作为关键字参数传入。...return a, b ... >>> f(1, b=2) # 只能传关键字参数 (1, 2) >>> f(1, 2) # 不能传定位参数 Traceback (most recent call last...): File "", line 1, in TypeError: f() takes 1 positional argument but 2 were given...>>> f(1, 2, 3) # 不能传定位参数 Traceback (most recent call last): File "", line 1, in TypeError...: f() takes 1 positional argument but 3 were given 仅限关键字参数不一定要有默认值，就像b一样，强制必须传入实参。

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Python中函数参数传递方法*args, **kwargs，还有其他

0 positional arguments but 1 positional argument (and 2 keyword-only arguments) were given transfer_money...('1234', to_account='6578', amount=9999) # won't work: TypeError: transfer_money() takes 0 positional...arguments but 3 were given transfer_money('1234', '6578', 9999) 在上面的函数中，*星号获得了了所有不匹配的位置参数，但是并没有一个变量来接受它...keyword arguments: 'x' print(len_new(x=[1, 1, 2, 2, 3, 3])) # Won't work: TypeError: len_new() takes...1 positional argument but 2 were given print(len_new([1, 1, 2, 2, 3, 3], True)) 6、最后把它们合在一起下面的函数是一个非常极端的例子

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python入门-4：类与对象

def __init__(self): ....... >>> mycar=moto('china','ak','2010') Traceback (most recent call last): File "", line 1, in... TypeError: __init__() takes 1 positional argument but 4 were given 在这个例子里面我们看到定义moto的时候报错了...def __init__(self,make,model,year): ... super()....def __init__(self,make,model,year,shape): ... super().__init__(make,model,year) ...

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Python中函数参数传递方法*args, **kwargs，还有其他

0 positional arguments but 1 positional argument (and 2 keyword-only arguments) were given transfer_money...('1234', to_account='6578', amount=9999) # won't work: TypeError: transfer_money() takes 0 positional...arguments but 3 were given transfer_money('1234', '6578', 9999) 在上面的函数中，*星号获得了了所有不匹配的位置参数，但是并没有一个变量来接受它...arguments: 'x' print(len_new(x=[1, 1, 2, 2, 3, 3])) # Won't work: TypeError: len_new() takes 1 positional...argument but 2 were given print(len_new([1, 1, 2, 2, 3, 3], True)) 6.

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Python中 *args 和 **kwargs 的含义？

) 运行结果： 1 2 3 4 2....b=2,c=3,d=4) 运行结果： a 1 b 2 c 3 d 4 下面演示个错误的案例，看到有个错误："func() takes 0 positional arguments but 4 were...given" ，“未定义位置型参数，却收到了4个参数。”...recent call last): File "F:/pyworkspace/hello.py", line 4, in func(1,2,3,4) TypeError...: func() takes 0 positional arguments but 4 were given 如果对于参考答案有不认同的，大家可以在评论区指出和补充，欢迎留言！

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Python编程常见出错信息及原因分析（3）

（1）不可哈希错误演示代码： >>> x = {[1], [2]} Traceback (most recent call last): File "", line 1,...in x = {[1], [2]} TypeError: unhashable type: 'list' >>> x = {[1]:1} Traceback (most recent...in func(3) TypeError: func() missing 1 required positional argument: 'b' >>> func(3, 5,..., 9) TypeError: func() takes from 2 to 3 positional arguments but 4 were given 一个比较类似的是序列解包的用法。...但是，下面的语句是错误： >>> x, y = 3, 5, 7 Traceback (most recent call last): File "", line 1, in <

8546 0

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完美解决丨TypeError: fun() takes 2 positional arguments but 3 were given

xadmin+django2.0删除用户报错，get_deleted_objects() takes 3 positional arguments but 5 were given

Python Django开发异常及其解决办法（一）

Django在根据models生成数据库表时报 init() missing 1 required positional argument on_d

xadmin 因为版本问题的错误

Python–socketserve源码分析(一)

paddleNLP-BUG和一些细节记录【一】

Django项目中xadmin遇到的坑记录

Python学习笔记（二）

Point(类与构造) Python

Python @staticmethod和@classmethod

Python - 3.8 新特性之仅位置参数 & 仅关键字参数

Python 中的默认值是什么？

Python函数中单独一个星号或斜线作为形参的含义

Python函数参数和注解是什么

Python中函数参数传递方法*args, **kwargs，还有其他

python入门-4：类与对象

Python中函数参数传递方法*args, **kwargs，还有其他

Python中 *args 和 **kwargs 的含义？

Python编程常见出错信息及原因分析（3）

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