arrayindex - 腾讯云开发者社区

; data = new byte[ (cacapacity >> 3) + 1]; } public void add(int num){ int arrayIndex...] |= 1 << position; } public boolean contain(int num){ int arrayIndex = num >> 3;...int position = num & 0x07; return ( data[arrayIndex] & (1 << position) ) !...= 0; } public void clear(int num){ int arrayIndex = num >> 3; int position =...num & 0x07; data[arrayIndex] &= ~(1 << position); } public static void main(String[

1.3K2 0

伪共享和缓存行填充，Java并发编程还能这么优化！

) { this.arrayIndex = arrayIndex; } public static void main(final String[] args...= --i) { longs[arrayIndex].value = i; } } public final static...this.arrayIndex = arrayIndex; } public static void main(final String[] args) throws Exception...this.arrayIndex = arrayIndex; } public static void main(final String[] args) throws Exception...= --i) { longs[arrayIndex].value = i; } } } @Contended public class

9252 0

您找到你想要的搜索结果了吗？

是的

没有找到

寻找性能更优秀的不可变小字典

true)] public string Directly() => _func(_yueluo); [Benchmark] public string ArrayIndex...Error StdDev Ratio RatioSD Rank Directly net461 .NET 4.6.1 0.9347 ns 0.0363 ns 0.0321 ns 1.00 0.00 1 ArrayIndex...53.36 1.64 4 Directly netcoreapp21 .NET Core 2.1 1.2153 ns 0.1168 ns 0.1434 ns 1.00 0.00 1 ArrayIndex...20.07 2.51 4 Directly netcoreapp31 .NET Core 3.1 0.7382 ns 0.1148 ns 0.1074 ns 1.00 0.00 1 ArrayIndex...30.61 4.20 4 Directly netcoreapp5 .NET Core 5.0 1.3323 ns 0.0527 ns 0.0493 ns 1.00 0.00 1 ArrayIndex

4020 0

经典算法之bitmap算法

bits[arrayIndex] |= 1 << position; } 代码如下: public class BitMap { //保存数据的 private byte[]...bits[arrayIndex] |= 1 << position; } public boolean contain(int num){ // num/8得到byte...[]的index int arrayIndex = num >> 3; // num%8得到在byte[index]的位置 int position...= num & 0x07; //将1左移position后，那个位置自然就是1，然后和以前的数据做&，判断是否为0即可 return (bits[arrayIndex...=0; } public void clear(int num){ // num/8得到byte[]的index int arrayIndex = num

1.2K3 0

JavaScript数组splice方法

= number3.splice(1,1,5,8) console.log(number3);//[10, 5, 8, 4, 7] console.log(removed3);//[] var arrayIndex...= [12,3,4,6,2,1,4]; //从数组开头查询4的下标位置 var indexNum = arrayIndex.indexOf(4); //从数组末尾查询4的下标位置 var...lastIndexNum = arrayIndex.lastIndexOf(4); var noIndexNum = arrayIndex.indexOf(14); console.log(indexNum

5791 0

assign-for-react

path = parsePath(paths.shift()); if (path.type === 'arrayIndex...throw new Error('bad end'); } return { indexs, type: 'arrayIndex...parsePath(paths.shift()); let key; do { if (path.type === 'arrayIndex...true; break; } const end = path.type === 'arrayIndex

4380 0

探讨缓存行与伪共享

implements Runnable { public final static long ITERATIONS = 500L * 1000L * 100L; private int arrayIndex...; private Type type; public FalseSharing(Type type, final int arrayIndex) { this.arrayIndex...= arrayIndex; this.type = type; } public void run() { long i = ITERATIONS + 1;...= --i) { Data.longs[arrayIndex].value = 0L; } break; case PADDING...= --i) { DataPadding.longs[arrayIndex].value = 0L; } break; }

7941 0

一丶简介

Value get(ArrayIndex index, const Value& defaultValue) const; 传入index获取数组元素 bool isValidIndex(ArrayIndex...index, const Value& newValue); //传入index插入数组元素 bool insert(ArrayIndex index, Value&& newValue);...bool removeIndex(ArrayIndex index, Value* removed);//删除指定index,删除的元素会通过参数2返回 bool empty() const; //...void resid(ArrayIndex newSize); 将数组元素扩充至N 3.4 JsonCpp中的对象操作 Members = vector Members getMemberNames...示例伪代码如下 Value& operator[](ArrayIndex index); Value& operator[](int index); const Value& operator[](ArrayIndex

1.4K6 0

用python帮博士师兄解决流态化专业问题

if np.isin(myPID, pid2): # 遍历出第二个文件里面的第二列的id和第一个文件里的id相等的一个array数组，每一个 # arrayIndex...就是第二个文件里相应的pid的行数 for arrayIndex in np.where(pid2 == myPID)[0]: # if t2[arrayIndex...# 把得到的数据保存到之前创建的travelTimeArray数组中 travelTimeArray = np.append(travelTimeArray, t2[arrayIndex

3011 0

自定义Dictionary支持线程安全

/// arrayIndex">The zero-based index in array at which copying begins.... /// arrayIndex is less than 0...-or-arrayIndex is equal to or greater than the length of array.... public void CopyTo(KeyValuePair[] array, int arrayIndex) {...(syncRoot) { ((ICollection>)d).CopyTo(array, arrayIndex

1.1K1 0

Java 中的伪共享详解及解决方案

4; // change public final static long ITERATIONS = 500L * 1000L * 1000L; private final int arrayIndex... { longs[i] = new VolatileLong(); } } public FalseSharing(final int arrayIndex...) { this.arrayIndex = arrayIndex; } public static void main(final String[] args)...= --i) { longs[arrayIndex].set(i); } } public static long sumPaddingToPreventOptimisation

5733 0

【算法千题案例】每日LeetCode打卡——75.字符串相加

var oneIndex = num1.Length - 1; var twoIndex = num2.Length - 1; var arrayIndex...--] - '0'; var sumTemp = initNum + oneNum + twoNum; forReturnArray[arrayIndex...sumTemp / 10; } if (initNum > 0) { forReturnArray[arrayIndex

2542 0

CA1010:集合应实现泛型接口

value) { return InnerList.IndexOf(value); } public void CopyTo(Book[] array, int arrayIndex...) { InnerList.CopyTo(array, arrayIndex); } } 若要解决此规则的冲突，请执行以下某个操作：实现泛型接口。...Contains(Book item) { return true; } void ICollection.CopyTo(Book[] array, int arrayIndex

6095 0

在20亿个随机整数中找出m是否存在，你打算怎么存数据呢？

bits[arrayIndex] |= 1 << position; } public boolean contain(int num){ // num/8得到byte...[]的index int arrayIndex = num >> 3; // num%8得到在byte[index]的位置 int position...= num & 0x07; //将1左移position后，那个位置自然就是1，然后和以前的数据做&，判断是否为0即可 return (bits[arrayIndex...=0; } public void clear(int num){ // num/8得到byte[]的index int arrayIndex =...bits[arrayIndex] &= ~(1 << position); } public static void main(String[] args) {

7013 0

html+css+JavaScript例题

-- 隐藏域是用来记录需要修改的学生对象所在的数组下标的 --> arrayIndex...; var address = fromObj.address.value; var phoneNumber = fromObj.phoneNumber.value; var arrayIndex... = fromObj.arrayIndex.value; //在控制台打印日志信息，看看收集表单数据的过程有没有出问题 console.log(name); console.log...age); console.log(sex); console.log(address); console.log(phoneNumber); console.log(arrayIndex...); //通过隐藏域记录的数组下标拿出学生对象 var stuObj = students[arrayIndex]; //将这个对象的数据重新覆盖一遍 stuObj.name

1.7K1 0

用golang写的golang解析json数据的包

gojson.Json(json).Getpath("trans_result", "src").Tostring()fmt.Println(c4) //today (5) func (j *Js) Arrayindex...\u4eca\u5929"},"result":["src","today","dst","\u4eca\u5929"]}`c7 := gojson.Json(json).Get("result").Arrayindex

1.6K11 0

C++在线五子棋对战（网页版）项目：jsoncpp

operator[](const char* key); Value removeMember(const char* key);//移除元素 const Value& operator[](ArrayIndex...index) const; //val["score"][0] Value& append(const Value& value);//添加数组元素val["score"].append(88); ArrayIndex

2932 0

Disruptor原理探讨

FalseSharing implements Runnable{ public final static long ITERATIONS = 500L * 1000L * 100L; private int arrayIndex...private static ValuePadding[] longsPadding; private boolean padding; public FalseSharing(final int arrayIndex..., boolean padding) { this.arrayIndex = arrayIndex; this.padding = padding; } public static...= --i) { if (padding) { longsPadding[arrayIndex].value = 0L; } else { longsNoPadding...[arrayIndex].value = 0L; } } } public final static class ValuePadding { protected

7671 0

【mongoDB查询进阶】聚合管道(二) -- 阶段操作符

db.articles.aggregate([ { $unwind: { path: '$comments', includeArrayIndex: 'arrayIndex...} } ]); 结果： [ { title: 'this is article A', author: 'John', _id: 1, comments: 'a', arrayIndex...: NumberLong(0) }, { title: 'this is article A', author: 'John', _id: 1, comments: 'b', arrayIndex...: NumberLong(1) }, { title: 'this is article A', author: 'John', _id: 1, comments: 'c', arrayIndex

2.5K3 0

一段代码，两倍时差，直击并发编程伪共享

NUM_THREADS = 4; public final static long ITERATIONS = 500L * 1000L * 1000L; private final int arrayIndex...static VolatileLong[] longs; public static long SUM_TIME = 0l; public FalseShare(final int arrayIndex...) { this.arrayIndex = arrayIndex; } private static void exeTest() throws InterruptedException...= --i) { longs[arrayIndex].value = i; } } public final static class VolatileLong

6093 0

点击加载更多

扫码

添加站长进交流群

领取专属 10元无门槛券

手把手带您无忧上云

BitMap

伪共享和缓存行填充，Java并发编程还能这么优化！

寻找性能更优秀的不可变小字典

经典算法之bitmap算法

JavaScript数组splice方法

assign-for-react

探讨缓存行与伪共享

一丶简介

用python帮博士师兄解决流态化专业问题

自定义Dictionary支持线程安全

Java 中的伪共享详解及解决方案

【算法千题案例】每日LeetCode打卡——75.字符串相加

CA1010:集合应实现泛型接口

在20亿个随机整数中找出m是否存在，你打算怎么存数据呢？

html+css+JavaScript例题

用golang写的golang解析json数据的包

C++在线五子棋对战（网页版）项目：jsoncpp

Disruptor原理探讨

【mongoDB查询进阶】聚合管道(二) -- 阶段操作符

一段代码，两倍时差，直击并发编程伪共享

扫码

相关资讯

热门标签

活动推荐

运营活动

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐