datetime.timedelta 内部只存储days,seconds,microseconds。
好多朋友都遇到过python推算时间的问题,有些把时间转换成整数做推算,这样遇到特殊的时间和日期就会出现错误,在python中时间的推算很简单,主要就是用到datetime.timedelta方法...(seconds=10)#增加10秒 >>> d2.strftime("%Y-%m-%d %H:%M:%S") '2013-09-02 17:11:17' >>> d2 = d1 + datetime.timedelta...(minutes=10)#增加10分钟 >>> d2.strftime("%Y-%m-%d %H:%M:%S") '2013-09-02 17:21:07' >>> d2 = d1 + datetime.timedelta...(hours=10)#增加10小时 >>> d2.strftime("%Y-%m-%d %H:%M:%S") '2013-09-03 03:11:07' >>> d2 = d1 + datetime.timedelta...(days=10)#增加10天 >>> d2.strftime("%Y-%m-%d %H:%M:%S") '2013-09-12 17:11:07' >>> d2 = d1 - datetime.timedelta
stamp = time.time() datetime.fromtimestamp(stamp) timedelta import datetime print('microseconds:', datetime.timedelta...(microseconds=1)) print('milliseconds:', datetime.timedelta(milliseconds=1)) print('seconds :', datetime.timedelta...(seconds=1)) print('minutes :', datetime.timedelta(minutes=1)) print('hours :', datetime.timedelta(hours...=1)) print('days :', datetime.timedelta(days=1)) print('weeks :', datetime.timedelta(weeks=1)) 加 就是 延后几秒
(milliseconds=1), #1毫秒 datetime.timedelta(seconds=1), #1秒 datetime.timedelta(minutes...=1), #1分钟 datetime.timedelta(hours=1), #1小时 datetime.timedelta(days=1), #1天...datetime.timedelta(weeks=1)]:#11周 #print i + ':' + i.total_seconds() print '%s = %s seconds'%...a = datetime.datetime.now() print '现在时间是:' print a print '加5小时之后变成:' b = a + datetime.timedelta(hours...=5) print b print '加一周之后变成:' c = a + datetime.timedelta(weeks=1) print c print '减去一周后变成:' d = a - datetime.timedelta
print(datetime.date.fromtimestamp(time.time())) #时间戳直接转换成日期格式 2018-07-30 print(datetime.datetime.now()+datetime.timedelta...(3)) #当前时间+3天 2018-08-02 16:19:46.772000 print(datetime.datetime.now()+datetime.timedelta(-3)) #当前时间-...3天 2018-07-27 16:23:08.552000 print(datetime.datetime.now()+datetime.timedelta(hours=3)) #当前时间+3小时 print...(datetime.datetime.now()+datetime.timedelta(minutes=30)) #当前时间+30分钟
引入datetime模块 import datetime #计算今天的时间 today = datetime.date.today() #计算昨天的时间 yesterday = today - datetime.timedelta...(days = 1) #计算明天的时间 tomorrow = today + datetime.timedelta(days = 1) #打印这三个时间 print(yesterday, today,...#引入datetime,calendar两个模块 import datetime,calendar last_friday = datetime.date.today() oneday = datetime.timedelta...(0) duration = sum([datetime.timedelta(minutes = m, seconds = s) for m, s in times], td) return...(0, 596) assert total_timer(times2) == datetime.timedelta(0, 815) print("Tests passed.
print(datetime.date.fromtimestamp(time.time())) 2019-03-07 # 当前时间+3天 print(datetime.datetime.now() + datetime.timedelta...(3)) 2019-03-10 16:22:14.560599 # 当前时间-3天 print(datetime.datetime.now() + datetime.timedelta(-3)) 2019...-03-04 16:22:14.568473 # 当前时间-3小时 print(datetime.datetime.now() + datetime.timedelta(hours=3)) 2019-03...-07 19:22:14.575881 # 当前时间+30分钟 print(datetime.datetime.now() + datetime.timedelta(minutes=30)) 2019-
(days=1) print("明天:", tomorrow) yesterday = today - datetime.timedelta(days=1) print("昨天:", yesterday...timedelta 可以通过指定天、秒、微秒、毫秒、分钟、小时和周来创建: 创建一个表示10天的 timedelta 对象 # 创建一个表示10天的 timedelta 对象 delta_days = datetime.timedelta...(days=5) delta2 = datetime.timedelta(days=10) print("delta1 < delta2:", delta1 < delta2) print("delta1...(days=10) delta_hours_minutes = datetime.timedelta(hours=2, minutes=30) delta_weeks = datetime.timedelta...(days=5) delta2 = datetime.timedelta(days=10) print("delta1 < delta2:", delta1 < delta2) print("delta1
get_third_last_workday(year, month): # 求出当月最后一天 last_day = datetime.date(year, month, 1) + datetime.timedelta...(days=31) last_day -= datetime.timedelta(days=last_day.day) while True: # 判断最后一天是周几...if last_day.weekday() < 5: break last_day -= datetime.timedelta(days=1) # 向前推算两个工作日得到倒数第三个工作日...third_last_workday = last_day - datetime.timedelta(days=2) while True: # 判断是否为工作日...if third_last_workday.weekday() < 5: break third_last_workday -= datetime.timedelta
match": { "updateTime": { "$gte":(datetime.datetime(year,month,day, 0, 0, 0, 000) - datetime.timedelta...(hours=8)), "$lte":(datetime.datetime(year,month,day, 23, 59, 59, 000) - datetime.timedelta...match": { "updateTime": { "$gte":(datetime.datetime(year,month,day, 0, 0, 0, 000) - datetime.timedelta...(hours=8)), "$lte":(datetime.datetime(year,month,day, 23, 59, 59, 000) - datetime.timedelta
datetime.timedelta:表示时间间隔,即两个时间点之间的长度。 datetime.tzinfo:与时区有关的相关信息。...[131]: a = datetime.datetime.now() In [132]: print a 2014-11-17 20:57:17.170393 In [133]: print a + datetime.timedelta...(days=-1) 2014-11-16 20:57:17.170393 In [137]: print a + datetime.timedelta(days=1) 2014-11-18 20:57:...17.170393 In [134]: print a + datetime.timedelta(hours=-1) 2014-11-17 19:57:17.170393 In [135]: print...a + datetime.timedelta(minutes=-1) 2014-11-17 20:56:17.170393 In [136]: print a + datetime.timedelta
today.month) print(today.day) ''' >>>2017-01-01 >>>2017 >>>1 >>>1 ''' # 获得明天, 其他依次类推 tomorrow = today + datetime.timedelta...(days=1) print(tomorrow) ''' >>>2017-01-02 ''' # 时间相减,相加同理 now = datetime.timedelta(days=0, hours=0..., minutes=3, seconds=50); pre = datetime.timedelta(days=0, hours=0, minutes=1, seconds=10); duration_sec...duration_sec)) print(type(now - pre)) print(duration_sec) print(duration_day) ''' >>> >>><class 'datetime.timedelta
hour = now.hour minute = now.minute second = now.second microsecond = now.microsecond midnight = now - datetime.timedelta...(hours=hour) - datetime.timedelta(minutes=minute) - datetime.timedelta(second=second) - datetime.timedelta
python日期加减 python 中日期類型是datetime.date 日期加减的结果,以及可以对日期相加減的類型是datetime.timedelta timedelta = date1 -...date2 date1 = date2 + timedelta datetime.timedelta(days, seconds, microseconds) d1 = datetime.date.today...() 加一天: d2 = d1 + datetime.timedelta(1) 減一天: d2 = d1 + datetime.timedelta(-1) python 如何计算时间差 Python...>>> d1 = datetime.datetime.now() >>> d3 = d1 + datetime.timedelta(hours=10) >>> d3.ctime() 上例演示了计算当前时间向后
获取上个月最后一天的日期(本月的第一天减去1天) last = datetime.date(datetime.date.today().year,datetime.date.today().month,1)-datetime.timedelta...() print (endtime - starttime).seconds 4.计算当前时间向后10个小时的时间 d1 = datetime.datetime.now() d3 = d1 + datetime.timedelta...import datetime, calendar def getYesterday(): today=datetime.date.today() oneday=datetime.timedelta...获取给定参数的前几天的日期,返回一个list def getDaysByNum(num): today=datetime.date.today() oneday=datetime.timedelta...bd=strtodatetime(beginDate,format) ed=strtodatetime(endDate,format) oneday=datetime.timedelta
datetime.datetime.now() print("当前时间:", current_time) print("\n") print("相差n天") n = 3 time_delta = datetime.timedelta...= "{0}天前".format(n) print(tips) print(other_time) print("\n") print("相差n小时") n = 15 time_delta = datetime.timedelta...current_time = datetime.datetime.now()获取当前的时间,包含年月日时分秒信息 time_delta = datetime.timedelta(days=n)定义了一个...datetime.timedelta对象,看了一下源码,支持以下参数 days seconds microseconds milliseconds minutes hours weeks 计算过去时间使用
).strftime("%Y-%m-%d %H:%M") # 2018-05-08 16:54 多加一天 import datetime print (datetime.datetime.now()+datetime.timedelta...strftime("%Y-%m-%d %H:%M:%S") # 2018-05-09 16:56:07 减一天 import datetime print (datetime.datetime.now()+datetime.timedelta...得到今天的日期可以用下面的代码: import datetime today = datetime.date.today() 得到昨天的日期可以用: yesterday = today – datetime.timedelta...(days=1) 得到明天的日期可以用: tomorrow = today + datetime.timedelta(days=1) 这一点很多文章都提到过。
datetime.timedelta:表示时间间隔,即两个时间点之间的长度。 datetime.tzinfo:与时区有关的相关信息。...time.time())) # 时间戳直接转成日期格式 2016-08-19 print(datetime.datetime.now()) print(datetime.datetime.now() + datetime.timedelta...(3)) # 当前时间+3天 print(datetime.datetime.now() + datetime.timedelta(-3)) # 当前时间-3天 print(datetime.datetime.now...() + datetime.timedelta(hours=3)) # 当前时间+3小时 print(datetime.datetime.now() + datetime.timedelta(minutes
获取获得一个月中的最后一天 :param any_day: 任意日期 :return: string """ next_month = any_day.replace(day=28) + datetime.timedelta...(days=4) # this will never fail return next_month - datetime.timedelta(days=next_month.day) # 注意...(days=4) # this will never fail return next_month - datetime.timedelta(days=next_month.day) # ...param any_day: 任意日期 :return: string """ next_month = any_day.replace(day=28) + datetime.timedelta...(days=4) # this will never fail return next_month - datetime.timedelta(days=next_month.day)
datetime.timedelta类的定义: class datetime.timedelta(days=0, seconds=0, microseconds=0, milliseconds=0, hours...(2020, 1, 22, 11, 17, 0, 214877) >>> dt + datetime.timedelta(-3) # 3天前 datetime.datetime(2020, 1, 16,...11, 17, 0, 214877) >>> dt + datetime.timedelta(hours=3) # 3小时后 datetime.datetime(2020, 1, 19, 14, 17..., 0, 214877) >>> dt + datetime.timedelta(hours=-3) # 3小时前 datetime.datetime(2020, 1, 19, 8, 17, 0, 214877...) >>> dt + datetime.timedelta(hours=3, seconds=30) # 3小时30秒后 datetime.datetime(2020, 1, 19, 14, 17,
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