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discord.py为什么@client.command不工作?

discord.py是一个用于创建Discord机器人的Python库。@client.command是discord.py库中的一个装饰器,用于定义一个命令函数。当用户在Discord中输入命令时,机器人会调用与该命令函数相对应的代码。

如果@client.command不工作,可能有以下几个原因:

  1. 未正确初始化客户端:在使用@client.command之前,需要先创建一个discord客户端对象,并正确初始化。示例代码如下:
代码语言:txt
复制
import discord
from discord.ext import commands

intents = discord.Intents.default()
intents.typing = False
intents.presences = False

client = commands.Bot(command_prefix='!', intents=intents)

@client.event
async def on_ready():
    print('Bot is ready.')

@client.command()
async def hello(ctx):
    await ctx.send('Hello!')

client.run('YOUR_BOT_TOKEN')
  1. 未正确定义命令函数:@client.command装饰器需要应用在一个函数上,并且该函数需要满足一定的条件。例如,函数需要是一个异步函数(使用async关键字),并且至少需要一个参数(通常命名为ctx),表示命令的上下文。示例代码如下:
代码语言:txt
复制
@client.command()
async def hello(ctx):
    await ctx.send('Hello!')
  1. 未正确处理事件循环:discord.py库需要一个事件循环来处理各种事件,例如接收消息、处理命令等。在使用discord.py之前,需要创建一个事件循环,并将客户端对象绑定到该事件循环上。示例代码如下:
代码语言:txt
复制
import asyncio

loop = asyncio.get_event_loop()
loop.run_until_complete(client.start('YOUR_BOT_TOKEN'))
  1. 未正确运行客户端:在使用discord.py之前,需要运行客户端以连接到Discord服务器。示例代码如下:
代码语言:txt
复制
client.run('YOUR_BOT_TOKEN')

综上所述,要使@client.command正常工作,需要正确初始化客户端、定义命令函数、处理事件循环,并运行客户端。如果仍然无法正常工作,可能是其他代码逻辑或配置问题,可以进一步检查和调试。

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