展开

关键词

Oracle二维表操作训练

—创建Employees create table Employees( employeeID varchar2(6) primary key, ename varchar2(10) not null primary key, departmentName varchar2(30) not null, note varchar2(16)); —创建Salary create table Salary( employeeID primary key, income number(8,2) not null, outcome number(8,2) not null);–插入测试数据 insert into Employees(Employeeid Departmentid) values(010001,‘王平’,to_date(‘1981-01-05’,‘yyyy-mm-dd’),‘女’,‘1’); insert into Employees(Employeeid Departmentid) values(010003,‘韦严平’,to_date(‘1979-11-05’,‘yyyy-mm-dd’),‘女’,‘2’); insert into Employees(Employeeid

22620

Ajax 案例之三级联动

* public class Employees {   private Integer employeeId;   private Integer departmentId;   private  = + employeeId +   , departmentId= + departmentId +   , lastName= + lastName +  +   , email= + email  ;       }   public void setEmployeeId(Integer employeeId) {   this.employeeId = employeeId;       }   ) {           String sql = SELECT employee_id employeeId, department_id departmentId, last_name lastName ).text(employeeId);                           $(#lastName).text(lastName);

67160
  • 广告
    关闭

    云产品限时秒杀

    云服务器1核2G首年38元,还有多款热门云产品满足您的上云需求

  • 您找到你想要的搜索结果了吗?
    是的
    没有找到

    递归查询

    复制代码 USE AdventureWorks; GO WITH DirectReports(ManagerID, EmployeeID, EmployeeLevel) AS ( SELECT ManagerID , EmployeeID, 0 AS EmployeeLevel FROM HumanResources.Employee WHERE ManagerID IS NULL UNION ALL SELECT HumanResources.Employee e INNER JOIN DirectReports d ON e.ManagerID = d.EmployeeID ) SELECT ManagerID, EmployeeID 复制代码 USE AdventureWorks; GO WITH DirectReports(ManagerID, EmployeeID, EmployeeLevel) AS ( SELECT ManagerID , EmployeeID, 0 AS EmployeeLevel FROM HumanResources.Employee WHERE ManagerID IS NULL UNION ALL SELECT

    41240

    SQL Server基础SQL脚本之创建架构、排序

    id int not null, name nvarchar)select * from AdventureWorks.HumanResources.Employeego--查找指定的列select EmployeeID from HumanResources.Employee--列的值升序排列select EmployeeID from HumanResources.Employeeorder by EmployeeID e.EmployeeID,e.Title into Empfrom AdventureWorks.HumanResources.Employee as eselect * from Empselect EmployeeID as Eid,Title as TName from Empselect E=EmployeeID,T=Title from Empselect EmployeeID EEE ,Title TTT from Empselect EmployeeID , EEE ,Title ,TTT from Empselect EmployeeID , EEEas ---> ,Title ,TTTas +Title

    44780

    sqlserver~创建函数

    dbo.ufn_FindReports; GO CREATE FUNCTION dbo.ufn_FindReports (@InEmpID INTEGER) RETURNS @retFindReports TABLE ( EmployeeID the employees who report to the --specific employee directly or indirectly.* AS BEGIN WITH EMP_cte(EmployeeID e.BusinessEntityID ) -- copy the required columns to the result of the function INSERT @retFindReports SELECT EmployeeID , FirstName, LastName, JobTitle, RecursionLevel FROM EMP_cte RETURN END; GO使用示例SELECT EmployeeID, FirstName

    16020

    MyBatis根据数组、集合查询

    collection属性值就是传入的List或array对象在自己封装的map里面的key.下面我们通过代码实践: select * from EMPLOYEES e where e.EMPLOYEE_ID in #{employeeId } select * from EMPLOYEES e where e.EMPLOYEE_ID in #{employeeId} select * from EMPLOYEES e e.DEPARTMENT_ID =#{departmentId} AND e.EMPLOYEE_ID in #{employeeId} Mapper类: public interface EmployeesMapper { List insertEmployeeRole(EmployeeRoleVo employeeRole);(EmployeeRoleVo中包含List roleList) insert into diary_employee_role (employeeId

    28020

    SQL2012_创建数据库,创建表,表的内外链接

    eidSELECT DISTINCT DepartmentID FROM HumanResources.EmployeeDepartmentHistory WHERE EmployeeID IN--返回多个结果的时候我们使用 in( select EmployeeID from HumanResources.Employee where Title =--返回一个结果的时候 使用的是= ( SELECT TITLE FROM HumanResources.Employee WHERE EmployeeID=20 ))select EmployeeID eid ,Title T into Emp from HumanResources.Employeeselect

    41190

    SQLServer中的CTE通用表表达式

    , COUNT(*), MAX(OrderDate) 8 FROM Orders 9 GROUP BY EmployeeID) AS oe(EmployeeID, NumOrders, MaxDate) Orders14 GROUP BY EmployeeID) AS om(EmployeeID, NumOrders, MaxDate)15 ON e.ReportsTo = om.EmployeeID Figure 3 使用 CTE 查询 1 ;WITH EmpOrdersCTE (EmployeeID, NumOrders, MaxDate) AS 2 ( 3 SELECT EmployeeID, Figure 4 引用另一个 CTE 的 CT;WITH EmpOrdersCTE (EmployeeID, NumOrders)AS( SELECT EmployeeID, COUNT(*) FROM 图 5 中的 EmpCTE 显示了收集销售副总裁的员工记录的定位点成员 (EmployeeID = 2)。定位点成员查询的最后一列返回 0 值,这表示分层顺序的第 0 层,也就是最顶层。

    68310

    SpringMVC中@RequestMapping的基本用法

    @RequestMapping(value=departments{departmentId}employees{employeeId}) public String findEmployee( @PathVariable String departmentId, @PathVariable String employeeId){ System.out.println(Find employee with ID: + employeeId + from department: + departmentId); return someResult; } 绑定多个参数6.

    60540

    MyBatis传入参数为list、数组、map写法

    所以这个时候collection属性值就是传入的List或array对象在自己封装的map里面的key.2.实践-实体类public class Employees { private Integer employeeId List,collection的值必须是:list,item的值可以随意,Dao接口中参数名字随意 select * from EMPLOYEES e where e.EMPLOYEE_ID in #{employeeId array,collection的值必须是:list,item的值可以随意,Dao接口中参数名字随意 select * from EMPLOYEES e where e.EMPLOYEE_ID in #{employeeId ,比如下面的departmentId select * from EMPLOYEES e e.DEPARTMENT_ID=#{departmentId} AND e.EMPLOYEE_ID in #{employeeId

    35430

    sql学习~with as用法

    CREATE TABLE dbo.MyEmployees ( EmployeeID smallint NOT NULL, FirstName nvarchar(30) NOT NULL, LastName NULL, DeptID smallint NOT NULL, ManagerID int NULL, CONSTRAINT PK_EmployeeID PRIMARY KEY CLUSTERED (EmployeeID , 4, 273) ,(23, NMary, NGibson, NMarketing Specialist, 4, 16);2.递归使用演示WITH DirectReports(ManagerID, EmployeeID , Title, EmployeeLevel) AS ( SELECT ManagerID, EmployeeID, Title, 0 AS EmployeeLevel FROM dbo.MyEmployees dbo.MyEmployees AS e INNER JOIN DirectReports AS d ON e.ManagerID = d.EmployeeID ) SELECT ManagerID, EmployeeID

    29020

    如何实现文档检索(下)

    db.Employee.find().sort({Employeeid:-1}).forEach(printjson)代码说明:上面的代码采用sort函数,该函数返回集合中的所有文档,然后使用修饰符更改返回记录的顺序 这里清楚地显示了按Employeeid降序返回的文档。值为1则按照升序。 db.Employee.remove({Employeeid:22})代码说明:上面的代码使用remove函数并指定了在这种情况下要删除Employee id为22的文档的条件。 db.Employee.update({Employeeid : 1},{$set: { EmployeeName : NewMartin}});命令执行成功,输出结果:? db.Employee.update( { Employeeid : 1 }, { $set : { EmployeeName : NewMartin Employeeid : 22 } })令执行成功

    19110

    由for V.S. for each想到的

    private int _age;        #endregion         Constructor#region Constructor        public Employee(string employeeID _employeeID = employeeID;            this._name = name;            this.         }        #endregion         Public Properties#region Public Properties         public string EmployeeID

    26090

    SQL Server 2008中的hierarchyid

    www.cnblogs.comchenxizhangarchive200904261444016.html一般我们使用的时候,如下面的例子 --创建表 CREATE TABLE Employees ( Org_Id hierarchyid NOT NULL, EmployeeId Level FROM Employees --查看陈希章的所有下属 DECLARE @BOSS hierarchyid SELECT @BOSS=Org_Id FROM Employees WHERE EmployeeID WHEREOrg_Id.IsDescendantOf(@BOSS)=1--查看赵六及其所有上级 DECLARE @Employee hierarchyid SELECT @Employee=Org_Id FROM Employees WHERE EmployeeID

    25810

    neo4j︱Cypher完整案例csv导入、关系联通、高级查询(三)

    CREATE INDEX ON :Product(productName);CREATE INDEX ON :Category(categoryID);CREATE INDEX ON :Employee(employeeID UNIQUE;同时,如果需要修改其中一部分内容,可参考下面案例: 如果Janet is now reporting to Steven那么久可以如以下方式进行修改:MATCH (mgr:Employee {EmployeeID :5})MATCH (emp:Employee {EmployeeID:3})-->()DELETE relCREATE (emp)-->(mgr)RETURN *;定位到emp,把有关联的都先删掉DELETE USING PERIODIC COMMITLOAD CSV WITH HEADERS FROM file:employees.csv AS rowMATCH (employee:Employee {employeeID : row.EmployeeID})MATCH (manager:Employee {employeeID: row.ReportsTo})MERGE (employee)-->(manager);那么最终就会生成如下的内容

    85520

    为or、in平反——or、in到底能不能利用索引?

    SELECT *FROM EmployeesWHERE (EmployeeID IN (2, 4, 5))SELECT *FROM EmployeesWHERE EmployeeID = 2 or EmployeeID  =  4 or EmployeeID =  5  这两个SQL语句的执行结果是一致的,执行计划也是一致的。 我们来看看EmployeeID字段在有无索引,有什么类型的索引的情况下,执行计划都是什么样子的1、 EmployeeID不是主键(没有聚集索引和非聚集索引) ?

    432100

    一脸懵逼学习Struts数据校验以及数据回显,模型驱动,防止表单重复提交的应用。

    );将user对象存放到值栈里面  9:综合应用:第一步:创建数据库和数据表,这里使用mysql默认的数据库test,创建数据表如下所示:-- 创建数据表CREATE TABLE employee( employeeId ) {29 根据员工的编号进行查询30 String sql =select * from employee where employeeId = ? where employeeId =? ) {22 if(employeeId ! = 0){ 23 return dao.getById(employeeId);24 }25 26 return null;27 }28 29 @Override30 public void save(

    29270

    Java设计模式之(十)——组合模式

    employeeRepo.getDepartmentEmployeeIds(department.getId()); List employeeIds = new ArrayList(); for (Long employeeId : employeeIds){ 根据 employeeId 查询数据库得到 salary 假设为 1000 double salary = 1000d; department.addSubNode (new Employee(employeeId,salary)); } }}4、组合模式优点①、高层模块调用简单一棵树形机构中的所有节点都是Component, 局部和整体对调用者来说没有任何区别,也就是说

    6620

    快速入门系列--MVC--02路由

    protected void Page_Load(object sender, EventArgs e)44 {45 if (this.IsPostBack)46 {47 return;48 }49 string employeeId = this.RouteData.Values as string;50 if (employeeId == * || string.IsNullOrEmpty(employeeId))51 {52 this.DetailsViewEmployee.Visible = false;55 }56 else57 {58 this.DetailsViewEmployee.DataSource = this.Repository.GetEmployees(employeeId

    25990

    定制 create-react-app:如何制作自己的模版

    Error(Please define `REACT_APP_EMPLOYEE_ID` and `REACT_APP_POSITION_ID` in your .env file); } const employeeID = process.env.REACT_APP_EMPLOYEE_ID const position = process.env.REACT_APP_POSITION_ID; return { employeeID , position }; } render() { const { employeeID, position } = this.getEnvValues(); return ( Welcome to Unicode Labs Employee ID: { employeeID } Position: { position } ); }} export default App;然后,到 react-scriptstemplatepublic

    41510

    相关产品

    • 人工智能

      人工智能

      提供全球领先的人脸识别、文字识别、图像识别、语音技术、NLP、人工智能服务平台等多项人工智能技术。

    相关资讯

    热门标签

    活动推荐

      运营活动

      活动名称
      广告关闭

      扫码关注云+社区

      领取腾讯云代金券