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BP: Useful report to list assigned employees

class-methods GET_ASSIGNED_EMPLOYEES importing ! class-methods GET_ASSIGNED_EMPLOYEES_BY_TAB importing ! --------------------------------+ * | Static Public Method ZCL_CRM_EMPLOYEE_MGNT_TOOL=>GET_ASSIGNED_EMPLOYEES -----------------------------------------------------------------</SIGNATURE> METHOD get_assigned_employees lt_employee = GET_ASSIGNED_EMPLOYEES( conv #( <user> ) ). GET RUN TIME FIELD lv_end.

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LeetCode 0181 - Employees Earning More Than Their Managers

Employees Earning More Than Their Managers Desicription The Employee table holds all employees including | +----+-------+--------+-----------+ Given the Employee table, write a SQL query that finds out employees

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    MySQL 8.0导入样例数据库employees

    1、下载 https://launchpad.net/test-db/employees-db-1/1.0.6 2、导入 [root@node1 app]# cd employees_db/ [root @node1 employees_db]# ll 总用量 164492 -rw-r--r-- 1 root root 752 11月 11 12:59 Changelog -rw-r--r- - 1 root root 6460 11月 11 12:59 employees_partitioned2.sql -rw-r--r-- 1 root root 7624 11月 11 12:59 employees_partitioned3.sql -rw-r--r-- 1 root root 5660 11月 11 12:59 employees_partitioned.sql .sql -rw-r--r-- 1 root root 4450 11月 11 12:59 test_employees_sha.sql [root@node1 employees_db]#

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    【DB笔试面试407】事务T执行完毕后,关系表EMPLOYEES的数据是()

    题目 已知下列员工关系表EMPLOYEES 员工号 部门 工资 04501 财务 3000 05601 市场 4000 03020 研发 3500 对该表的工资属性和完整性约束为:2000≤工资≤ 操作1:INSERT INTO EMPLOYEES VALUES('03650','研发','4600'); 操作2:UPDATE EMPLOYEES SET 工资=工资*1.2 WHERE 部门='市场 ' OR 部门='研发'; 事务T执行完毕后,关系表EMPLOYEES的数据是() A、 员工号 部门 工资 04501 财务 3000 05601 市场 4000 03020 研发 3500 03650

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    ORA-01400: 无法将 NULL 插入 (S01.A02_EMPLOYEES.ID) 错误

    这个问题很多时候是没有为该表建立触发器导致的,或者是sequence没建立,或者是trigger没建立。

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    MySQL 8.0角色与授权

    1、用户 已经存在了employeesemployees_read用户,新建一个写用户 mysql> CREATE USER 'employees_write'@'%' IDENTIFIED BY ; Query OK, 0 rows affected (0.01 sec) (2)只读角色 mysql> grant select on employees.* to employees_r; Query | % | employees | N | | % | employees_r | % | employees_read `employees` TO `employees_read`@`%` | | GRANT `employees_r`@`%` TO `employees_read`@`%` `employees`@`%` | | GRANT `employees_admin`@`%` TO `employees`@`%` | +----

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    MySQL如何选择合适的索引

    `id` AS `id`,`employees`.`name` AS `name`,`employees`.`age` AS `age`,`employees`. `position` AS `position`,`employees`.`hire_time` AS `hire_time` from `employees` where (`employees`. `name` > 'a') order by `employees`. `id` AS `id`,`employees`.`name` AS `name`,`employees`.`age` AS `age`,`employees`. `position` AS `position`,`employees`.`hire_time` AS `hire_time` from `employees` where (`employees`.

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    MySQL8.0新特性-invisible indexes

    `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`. `hire_date` AS `hire_date` from `employees`.`employees_1` where (`employees`.`employees_1`. `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`. `hire_date` AS `hire_date` from `employees`.`employees_1` where (`employees`.`employees_1`. `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`.

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    MySQL8.0新特性——invisible indexes

    `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`. `hire_date` AS `hire_date` from `employees`.`employees_1` where (`employees`.`employees_1`. `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`. `hire_date` AS `hire_date` from `employees`.`employees_1` where (`employees`.`employees_1`. `employees_1`.`emp_no` AS `emp_no`,`employees`.`employees_1`.

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    单表超 100000000 条记录的数据库结构变更,你能做到在线平滑变更吗?

    这里测试基于 employees 表创建 employees_ptosc 表: mysql root@localhost:employees> create table employees_ptosc `employees_ptosc`... `employees`.`employees_ptosc` was not altered. `employees` FOR EACH ROW DELETE IGNORE FROM `employees`.`_employees_new` WHERE `employees`. `employees` 200 Query RENAME TABLE `employees`.`_employees_new` TO `employees`. `employees` TO `employees`.`_employees_old`, `employees`.`_employees_new` TO `employees`.

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    如何理解和使用Python中的列表

    '] print('修改前:',employees) employees[0] = 'Mary' employees[1] = 'Bunpoat' print('修改后:',employees) 运行结果 ,'Jack'] print('修改前:',employees) employees[0:2] = ['Mary','Bunpoat'] #修改employees[0]为Mary,employees[1 修改前:',employees) del employees[:] #删除employees[0] 和 employees[1] print('修改后:',employees) employees :',employees) employees.clear() print('修改后:',employees) 运行结果: ? 'Frank','Jack'] print('修改前:',employees) employees.remove('Yuki') print('修改后:',employees) employees.remove

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    MySQL练习七

    题目 有一个员工employees表简况如下: 请你查找employees里入职员工时间排名倒数第三的员工所有信息,以上例子输出如下: 2 表结构 drop table if exists ` employees` ; CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, `birth_date` date NOT NULL, `first_name VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26'); INSERT INTO employees VALUES(10002,' employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); INSERT INTO employees VALUES -01-22'); 答案 select * from employees where hire_date = ( select distinct hire_date from employees

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    玩转Mysql系列 - 第12篇:子查询(非常重要,高手必备)

    浏览器中打开链接:http://www.itsoku.com/article/209 mysql中执行里面的javacode2018_employees库部分的脚本。 成功创建javacode2018_employees库及5张表,如下: 表名 描述 departments 部门表 employees 员工信息表 jobs 职位信息表 locations 位置表(部门表中会用到 ①的结果*/ SELECT * FROM employees a WHERE a.salary > (SELECT salary FROM employees (salary) FROM employees; /*③方式1:查询员工信息*/ SELECT * FROM employees a WHERE a.employee_id = (SELECT min( FROM employees); /*方式2*/ SELECT * FROM employees a WHERE (a.employee_id, a.salary) = (SELECT

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    MySQL练习九:查找最晚入职员工的所有信息

    有一个员工employees表简况如下: 0BFB4D140D9C3E92AF681D9F9CB92D55 请你查找employees里最晚入职员工的所有信息,以上例子输出如下: D2ABA1E2F5834850B16146F168AC5476 对应SQL语句: DDL drop table if exists `employees` ; CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL VALUES(10001,'1953-09-02','Georgi','Facello','M','1986-06-26'); INSERT INTO employees VALUES(10002,' employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); INSERT INTO employees VALUES -01-22'); 参考答案: SELECT * FROM employees where hire_date = (SELECT hire_date from employees order by

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    MySQL 8.0用户管理

    3、授权 mysql> grant select(first_name, last_name) on employees.employees to 'employees_read'@'%'; Query mysql> select * from employees.employees; ERROR 1143 (42000): SELECT command denied to user 'employees_read '@'localhost' for column 'emp_no' in table 'employees' mysql> select first_name,last_name from employees.employees 用户 [root@node1 ~]# mysql -u employees -p123 -e "select * from employees.employees limit 10" mysql: [Warning affected (0.00 sec) mysql> employees用户下只有employees数据库

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    MySQL练习十:查找入职员工时间排名倒数第三的员工所有信息

    题目:有一个员工employees表简况如下: 0BFB4D140D9C3E92AF681D9F9CB92D55 (1) 结果:请你查找employees里入职员工时间排名倒数第三的员工所有信息,以上例子输出如下 : 2A26AB183839E3A01C933AE5A75B6D2F 数据表:表结构 drop table if exists `employees` ; CREATE TABLE `employees employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); INSERT INTO employees VALUES select * from employees where hire_date = (select distinct hire_date from employees order by hire_date select * from employees where hire_date = (select hire_date from employees group by hire_date order

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    MySQL练习二:查询入职日期倒数第三的员工信息

    题目: 有一个员工employees表简况如下: 结果: 请你查找employees里入职员工时间排名倒数第三的员工所有信息,以上例子输出如下: [2A26AB183839E3A01C933AE5A75B6D2F ] 数据表: 表结构 drop table if exists `employees` ; CREATE TABLE `employees` ( `emp_no` int(11) NOT NULL, employees VALUES(10007,'1957-05-23','Tzvetan','Zielinski','F','1989-02-10'); INSERT INTO employees VALUES select * from employees where hire_date = (select distinct hire_date from employees order by hire_date select * from employees where hire_date = (select hire_date from employees group by hire_date order

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    如何使用Sentry实现HiveImpala的数据脱敏

    表及employees_mask视图。 /employees/employees.csv [root@ip-172-31-16-68 datamasking]# (可左右滑动) [eoosedypu9.jpeg] 4.验证employees 通过上图可以看出Group A可以访问视图employees_unmasked里未经遮蔽的数据,但是不能直接访问表employees,当然也不能访问底层文件。 而Group B只能访问employees_masked视图里的数据,这个是有敏感数据被屏蔽了的,因为Sentry的控制,他没权限直接访问employees表或者通过HDFS文件去获取真实的被屏蔽的值。 和employees_masked视图数据 Hive引擎查询employees_masked脱敏视图数据 [clm7jku5l5.jpeg] Hive引擎查询employees_unmasked未脱敏视图

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    MySQL|索引应用

    CASCADE,表明此表的emp_no引用的是employees表的emp_no,同时ON DELETE CASCADE指明一旦删除employees的某emp_no的记录,相应也会在这个表中删除这条记录 02 employees示例库 看这个概念前,先介绍一个实例库。 导入MySql的employees库,下载地址: https://dev.mysql.com/doc/employee/en/employees-installation.html 解压缩后,找到 employees.sql 没有添加组合索引前的查询: SELECT * FROM employees.employees WHERE first_name='Eric' AND last_name='Anido' 耗时:0.609s 添加组合索引: ALTER TABLE employees.employees ADD INDEX `first_name_last_name4` (first_name, last_name(4))

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