iOS Firebase -How将从不同节点中删除具有相同密钥的子节点

let ref = Database.database().reference()
let childRef = ref.child("parent").child("child")
childRef.removeValue()

const functions = require('firebase-functions');
const admin = require('firebase-admin');
admin.initializeApp();

exports.deleteDuplicateNodes = functions.database.ref('/parent/{parentId}/child/{childId}')
    .onDelete((snapshot, context) => {
        const parentId = context.params.parentId;
        const childId = context.params.childId;
        const parentRef = snapshot.ref.parent;

        // 查询具有相同密钥的子节点
        return parentRef.orderByChild('key').equalTo(childId).once('value')
            .then((snapshot) => {
                // 删除所有具有相同密钥的子节点
                const updates = {};
                snapshot.forEach((childSnapshot) => {
                    updates[childSnapshot.key] = null;
                });
                return parentRef.update(updates);
            });
    });