stream().skip(8);
skipList.forEach(System.out::println);
System.out.println("----------...reduce()
*/
public static void test7(){
List ints = Lists.newArrayList(22,1,2,3,4,5,6,7,8,9,10,45,78,67...处理这种多条件的筛选时,比集合简单很多
public static void test5(){
List fruits = test4();
//河南 苹果 大于8元...))
.filter(f -> f.getName().equals("苹果"))
.filter(f -> f.getPrice() > 8)...柑橘","red","河南",5,800,"好吃");
Fruit f7 = new Fruit("柑橘","red","山西",12,500,"好吃");
Fruit f8