javascript GET方法

var xhr = new XMLHttpRequest();
xhr.onreadystatechange = function() {
    if (xhr.readyState == 4 && xhr.status == 200) {
        console.log(xhr.responseText);
    }
};
xhr.open("GET", "https://api.example.com/data", true);
xhr.send();

fetch("https://api.example.com/data")
    .then(response => {
        if (!response.ok) {
            throw new Error("Network response was not ok");
        }
        return response.json();
    })
    .then(data => console.log(data))
    .catch(error => console.error("There was a problem with the fetch operation:", error));