js累加

let numbers = [1, 2, 3, 4, 5];
let sum = 0;

for (let i = 0; i < numbers.length; i++) {
    sum += numbers[i];
}

console.log(sum); // 输出：15

let numbers = [1, 2, 3, 4, 5];

let sum = numbers.reduce((accumulator, currentValue) => {
    return accumulator + currentValue;
}, 0);

console.log(sum); // 输出：15

let numbers = [1, 2, 3, 4, 5];
let sum = 0;

for (let i = 0; i <= numbers.length; i++) { // 错误的循环条件
    sum += numbers[i];
}

console.log(sum); // 可能会导致错误的结果或运行时错误

let numbers = [1, 2, 3, 4, 5];
let sum = 0;

for (let i = 0; i < numbers.length; i++) { // 正确的循环条件
    sum += numbers[i];
}

console.log(sum); // 输出：15