linux 获得光标位置

echo -e "\033[6n"

#include <stdio.h>

int main() {
    printf("\033[6n");
    fflush(stdout);

    int row = 0, col = 0;
    char buf[32];
    if (fgets(buf, sizeof(buf), stdin) != NULL) {
        sscanf(buf, "\033[%d;%dR", &row, &col);
    }

    printf("Row: %d, Col: %d
", row, col);
    return 0;
}

gcc -o get_cursor_position get_cursor_position.c
./get_cursor_position

import sys
import tty
import termios

def get_cursor_position():
    fd = sys.stdin.fileno()
    old_settings = termios.tcgetattr(fd)
    try:
        tty.setraw(sys.stdin.fileno())
        sys.stdout.write('\033[6n')
        sys.stdout.flush()
        while True:
            ch = sys.stdin.read(1)
            if ch == 'R':
                break
            pos = ''
            while True:
                ch = sys.stdin.read(1)
                if ch.isdigit():
                    pos += ch
                else:
                    break
            row, col = map(int, pos.split(';'))
            return row, col
    finally:
        termios.tcsetattr(fd, termios.TCSADRAIN, old_settings)

row, col = get_cursor_position()
print(f"Row: {row}, Col: {col}")