...arr].sort((a, b) => b - a).slice(0, n);
maxN([1, 2, 3]); // [3]
maxN([1, 2, 3], 2); // [3,2]
84、minDate...const minDate = (...dates) => new Date(Math.min.apply(null, ...dates));
const array = [
new Date(2017..., 4, 13),
new Date(2018, 2, 12),
new Date(2016, 0, 10),
new Date(2016, 0, 9)
];
minDate(array);