mysql查询结果怎么输出

SELECT * FROM your_table;

mysql -u username -p -e "SELECT * FROM your_table;" > output.txt

import mysql.connector

mydb = mysql.connector.connect(
  host="localhost",
  user="yourusername",
  password="yourpassword",
  database="yourdatabase"
)

mycursor = mydb.cursor()

mycursor.execute("SELECT * FROM your_table")

myresult = mycursor.fetchall()

for row in myresult:
  print(row)

const mysql = require('mysql');

const connection = mysql.createConnection({
  host     : 'localhost',
  user     : 'yourusername',
  password : 'yourpassword',
  database : 'yourdatabase'
});

connection.connect();

connection.query('SELECT * FROM your_table', function (error, results, fields) {
  if (error) throw error;
  console.log(results);
});

connection.end();

<?php
$servername = "localhost";
$username = "yourusername";
$password = "yourpassword";
$dbname = "yourdatabase";

// 创建连接
$conn = new mysqli($servername, $username, $password, $dbname);

// 检查连接
if ($conn->connect_error) {
  die("连接失败: " . $conn->connect_error);
}

$sql = "SELECT * FROM your_table";
$result = $conn->query($sql);

if ($result->num_rows > 0) {
  // 输出数据
  while($row = $result->fetch_assoc()) {
    echo "id: " . $row["id"]. " - Name: " . $row["name"]. "<br>";
  }
} else {
  echo "0 结果";
}
$conn->close();
?>