针对多列表嵌套,如何获取所有元素?...之前使用for循环+if判断,进行分解,如下:
for first_layer in lists:
if isinstance(first_layer,list):
...second_layer:
print third_layer
else:
print first_layer
但是,若遇到列表有4重嵌套...、5重嵌套...等等,代码显得无比复杂、臃肿。.../usr/bin/env python
#coding:utf-8
fruit=['a','b',123,['c',345,'d',['e','f',90],22,'cc'],'po',34]
def