redux-form:如何在Promise中抛出新的SubmissionError？

import { SubmissionError } from 'redux-form';

const submitForm = async (values) => {
  try {
    // 异步操作，例如发送表单数据到服务器
    const response = await fetch('/api/submit', {
      method: 'POST',
      body: JSON.stringify(values),
    });

    if (!response.ok) {
      // 如果服务器返回错误状态码，抛出SubmissionError
      const errorData = await response.json();
      throw new SubmissionError(errorData);
    }

    // 处理成功提交的情况
  } catch (error) {
    // 处理其他错误
  }
};

import { reduxForm } from 'redux-form';

const MyForm = (props) => {
  const { handleSubmit } = props;

  const onSubmit = (values) => {
    handleSubmit(submitForm)(values);
  };

  return (
    <form onSubmit={onSubmit}>
      {/* 表单字段 */}
    </form>
  );
};

export default reduxForm({
  form: 'myForm',
})(MyForm);