$S$表示一个二进制集合.$S$中第$i$位是$1$表示该集合包含标号是$i$的技能
pam_sss.so forward_pass #auth sufficient pam_ldap.so forward_pass auth required...pam_unix.so sha512 shadow nullok try_first_pass use_authtok password sufficient pam_sss.so...use_authtok #password sufficient pam_ldap.so use_authtok password required pam_deny.so...pam_sss.so forward_pass #auth sufficient pam_ldap.so forward_pass auth required...pam_unix.so sha512 shadow nullok try_first_pass use_authtok password sufficient pam_sss.so
T (x )是分布的充分统计量（sufficient statistic ） η 是自然参数。对于有限的函数 ? 而言， η 的集合被称为自然参数空间。...Exponential families have sufficient statistics that can summarize arbitrary amounts of independent identically...具体解释如下（没看到的就不解释了……）： （1） 指数函数的充分统计量的可以从大量的i.i.d.数据中归结为估计的几个值（即T (x )），这点在 sufficient statistics中也有说明...Only if that family is an exponential family is there a (possibly vector-valued) sufficient statistic...sufficient statistic充分统计量 统计量T(X ) 对于给定参数θ 而言是充分的 是指对于X 的条件概率而言, 给定统计量T (X ), 则不依赖于参数 θ。 ?
grep "pam_rootok" 123 ⨯ grep: /etc/pam.d: 是一个目录 /etc/pam.d/su:auth sufficient..."sufficient pam_rootok.so")..../etc/pam.d/runuser:auth sufficient pam_rootok.so /etc/pam.d/chsh:auth sufficient... pam_rootok.so /etc/pam.d/chfn:auth sufficient pam_rootok.so 测试 使用root执行命令 # ln
pam_sss.so forward_pass auth sufficient pam_ldap.so forward_pass auth required...pam_unix.so sha512 shadow nullok try_first_pass use_authtok #password sufficient pam_sss.so...use_authtok password sufficient pam_ldap.so use_authtok password required pam_deny.so...pam_unix.so sha512 shadow nullok try_first_pass use_authtok #password sufficient pam_sss.so...use_authtok password sufficient pam_ldap.so use_authtok password required pam_deny.so
the Shadow `su' service # # This allows root to su without passwords (normal operation) auth sufficient..."sufficient pam_rootok.so")....# auth sufficient pam_wheel.so trust # Uncomment this if you want members of a specific group...@include common-auth @include common-account @include common-session 重点是这行： auth sufficient...pam_rootok.so sufficient 表示只要这行满足，直接返回登录成功 好，我们再来看一下 Linux man 手册上关于 pam_rootok.so 的介绍 ?
will be destroyed the next time authconfig is run. auth required pam_env.so auth sufficient... pam_fprintd.so auth sufficient pam_unix.so nullok try_first_pass auth requisite ...= 500 quiet auth required pam_deny.so account required pam_unix.so account sufficient... pam_localuser.so account sufficient pam_succeed_if.so uid < 500 quiet account required...difok=3 minlen=8 ucredit=-1 lcredit=-1 dcredit=-1 dictpath=/usr/share/cracklib/pw_dict password sufficient
=5 lock_time=30 even_deny_root root_unlock_time=30 auth required pam_env.so auth sufficient...= 500 quiet auth required pam_deny.so account required pam_unix.so account sufficient... pam_localuser.so account sufficient pam_succeed_if.so uid < 500 quiet account required... pam_permit.so password requisite pam_cracklib.so try_first_pass retry=3 type= password sufficient
will be destroyed the next time authconfig is run. auth required pam_env.so auth sufficient...pam_unix.so nullok try_first_pass auth requisite pam_succeed_if.so uid >= 500 quiet auth sufficient...auth required pam_deny.so account required pam_unix.so broken_shadow account sufficient...required pam_permit.so password requisite pam_cracklib.so try_first_pass retry=3 password sufficient... pam_unix.so md5 shadow nullok try_first_pass use_authtok password sufficient pam_winbind.so
pam_sss.so use_first_pass auth sufficient pam_ldap.so use_first_pass auth required...pam_deny.so account required pam_unix.so account sufficient pam_localuser.so account...sufficient pam_succeed_if.so uid < 500 quiet account [default=bad success=ok user_unknown...pam_unix.so sha512 shadow nullok try_first_pass use_authtok #password sufficient pam_sss.so...use_authtok password sufficient pam_ldap.so use_authtok password required pam_deny.so
pam_localuser.so account sufficient pam_succeed_if.so uid < 500 quiet account required...（如果成功，则应该继续往下走） sufficient的大概意思是，如果失败了也继续往下走，且本次失败完全不影响最终结果。如果成功，且前面的required没有过失败，则立刻返回成功，不继续往下走了。...特别注意的是，网上一般对sufficient的解释很多都是错的，变成了只要它成功了，无论前面是否有过失败，都返回成功，比如： ?...pam_fprintd好像是什么指纹验证，而其控制标记是sufficient，所以失败也无所谓。...所以，由于这里用的是include，而system-auth的pam_unix.so的控制符是sufficient，所以，pam_tally2应该放置于include语句之前才能起效果。
[root@svr5 shell]# vim /etc/pam.d/su #%PAM-1.0 auth sufficient pam_rootok.so # Uncomment...#auth sufficient pam_wheel.so trust use_uid # Uncomment the following line to require...pam_wheel.so use_uid //将行首的#去掉使其成为有效行 auth include system-auth account sufficient
# vim /etc/pam.d/su OR $ sudo vim /etc/pam.d/su 之后添加以下配置 auth sufficient pam_rootok.so auth [success...=ignore default=1] pam_succeed_if.so user = postgres auth sufficient pam_succeed_if.so use_uid...auth sufficient pam_succeed_if.so use_uid user ingroup postgres 保存文件并关闭它。
distinct because they possess a variety of desirable properties, most importantly the existence of a sufficient...distributions, in terms of natural parameters, and for defining useful sample statistics, called the natural sufficient
private static final int KEY_GEN_ITERATION_COUNT = 1024; // *** POINT 5 *** Use a key of length sufficient...bytes public static final int IV_LENGTH_BYTES = 16; // *** POINT 3 *** Use a key of length sufficient...SecretKey secretKey = null; try { // *** POINT 3 *** Use a key of length sufficient...private static final int KEY_GEN_ITERATION_COUNT = 1024; // *** POINT 5 *** Use a key of length sufficient...private static final String KEY_ALGORITHM = "HmacSHA256"; // *** POINT 3 *** Use a key of length sufficient
has not accepted any resources; check your cluster UI to ensure that workers are registered and have sufficient...has not accepted any resources; check your cluster UI to ensure that workers are registered and have sufficient...has not accepted any resources; check your cluster UI to ensure that workers are registered and have sufficient...has not accepted any resources; check your cluster UI to ensure that workers are registered and have sufficient...has not accepted any resources; check your cluster UI to ensure that workers are registered and have sufficient
Nov 2018 14:26:17 +0800 Wed, 21 Nov 2018 22:42:01 +0800 KubeletHasSufficientDisk kubelet has sufficient...Nov 2018 14:26:17 +0800 Wed, 21 Nov 2018 22:42:01 +0800 KubeletHasSufficientMemory kubelet has sufficient...Nov 2018 14:26:17 +0800 Wed, 21 Nov 2018 22:42:01 +0800 KubeletHasSufficientPID kubelet has sufficient
在原内容之前添加，原内容不注销： auth sufficient /lib/security/pam_userdb.so db=/etc/vstpd/vsftpduser //注意不加.db account...在原内容之前添加： auth sufficient /lib/security/pam_mysql.so user=mysqlvsftpd passwd=123456 localhost=host db...=vsftpd table=users usercolumn=name passwdcolumn=pwd auth sufficient /lib/security/pam_mysql.so user...但是sufficient表示通过这个模块就不进行下面的检查了。这样可以让本地用户也可以登录 一下是设置虚拟用户的权限,最好将下面5个anon—放到用户配置文件里面去。
Your account does not have sufficient permissions to modify containers解决：直接把 BuildSettings – Code Signing.../ios/324142.html参考：https://stackoverflow.com/questions/40596802/xcode-8-your-account-does-not-have-sufficient-permissions-to-modify-containers2
QA Your account does not have sufficient permissions to modify containers 解决：直接把 BuildSettings – Code.../ios/324142.html 参考：https://stackoverflow.com/questions/40596802/xcode-8-your-account-does-not-have-sufficient-permissions-to-modify-containers
领取专属 10元无门槛券
手把手带您无忧上云
云服务器
即时通信 IM
ICP备案
对象存储
实时音视频
