TOP 的语法 语法很简单，可以将TOP加在任何如 SELECT、DELETE, INSERT, or UPDATE 的语句中： TOP (expression) [PERCENT] [WITH TIES...可选项WITH TIES ，用来包含具有系统值得数据，需要注意的是该选项支队带有Order by的子句有效。 举例说明： 现有数据： ?...Number) PERCENT SalesAgent, Region, SalesAmount FROM dbo.HectorSales ORDER BY SalesAmount DESC; 使用 WITH TIES...实际是3个 SELECT TOP(2) WITH TIES SalesAgent, Region, SalesAmount FROM dbo.HectorSales ORDER BY SalesAmount...DELETE FROM dbo.HectorSales WHERE SalesAgent in (SELECT TOP(2) WITH TIES SalesAgent FROM dbo.HectorSales
/brucethemoose/CapyTessBorosYi-34B-200K-DARE-Ties/model-00001-of-00008.safetensors Loading model file.../brucethemoose/CapyTessBorosYi-34B-200K-DARE-Ties/model-00001-of-00008.safetensors Loading model file.../brucethemoose/CapyTessBorosYi-34B-200K-DARE-Ties/model-00002-of-00008.safetensors ....../brucethemoose/CapyTessBorosYi-34B-200K-DARE-Ties')) Loading vocab file '...../brucethemoose/CapyTessBorosYi-34B-200K-DARE-Ties/ggml-model-f16.gguf' to '..
1、 TOP用法 语法格式： TOP ( expression ) [ PERCENT ] [ WITH TIES ] expression：返回行数的数值表达式 PERCENT：指返回的结果集行的百分比...解决列中存在重复值时返回结果的不确定性问题，可以使用WITH TIES 关键字。该关键字将指定返回包含ORDER BY子句返回的最后一个值的所有行，这样将超过expression指定的数量。...示例： SELECT TOP 2 WITH TIES FROM UserInfo ORDER BY CreateDate 2、OFFSET-FETCH用法 SQL Server 2012版本引入了对...但OFFSET-FETCH不支持PERCENT和WITH TIES选项，而TOP支持。
. - Scissors beats paper. 0 Wins, 0 Losses, 0 Ties Enter your move: (R)ock (P)aper (S)cissors or (Q).... wins = 0 losses = 0 ties = 0 while True: # Main game loop....print('{} Wins, {} Losses, {} Ties'.format(wins, losses, ties)) print('Enter your move: (R)ock...ties = ties + 1 elif playerMove == 'ROCK' and computerMove == 'SCISSORS': print('You win!...2 Wins, 0 Losses, 0 Ties `--snip--` SCISSORS versus... 1... 2... 3... PAPER You win!
- GGUF# https://huggingface.co/TheBloke/Capybara-Tess-Yi-34B-200K-DARE-Ties-GGUFTheBloke/Capybara-Tess-Yi...-34B-200K-DARE-Ties-GGUF capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf# Nous Capybara 34B - GGUF# https...capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf --local-dir ....-34B-200K-DARE-Ties-GGUF │ └── capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf └── Nous-Capybara.../models/TheBloke/Capybara-Tess-Yi-34B-200K-DARE-Ties-GGUF/capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf
如果你懒得进行这个量化步骤，可以直接下载 HuggingFace 社区其他社区用户量化好的版本： •TheBloke/Capybara-Tess-Yi-34B-200K-DARE-Ties-GGUF[9...-34B-200K-DARE-Ties-GGUF capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf # Nous Capybara 34B - GGUF...capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf --local-dir ....Capybara-Tess-Yi-34B-200K-DARE-Ties-GGUF │ └── capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf.../models/TheBloke/Capybara-Tess-Yi-34B-200K-DARE-Ties-GGUF/capybara-tess-yi-34b-200k-dare-ties.Q4_K_M.gguf
ROWS } ] [ FETCH { FIRST | NEXT } [ { rowcount | percent PERCENT } ] { ROW | ROWS } { ONLY | WITH TIES...如果您使用WITH TIES 关键字，您的查询还将包括与最后一个合格行的排序键匹配的所有行。...您可以选择使用WITH TIES 返回关系值。...SELECT employee_id, last_name, salary FROM employees ORDER BY salary FETCH FIRST 5 PERCENT ROWS WITH TIES...employee_id, last_name, salary FROM employees ORDER BY salary OFFSET 5 ROWS FETCH FIRST 5 PERCENT ROWS WITH TIES
代码： https://github.com/Digitous/LLM-SLERP-Merge 3、TIES 传统的模型合并在处理不同模型参数之间会获得不同的干扰。...为了克服这些挑战，TIES方法引入了三个步骤: 1、重置在微调期间只发生轻微变化的参数。这一步有助于减少冗余。 2、解决了由于不同模型的参数值符号不同而产生的冲突。...ties - merge方法已被证明在各种设置下优于几种现有的merge方法。它有效地解决了干扰问题，特别是符号干扰，增强了合并模型的整体性能。...它主要关注于学习类似(同源)模型的参数，它使用与TIES类似的方法，但有两个主要区别: Delta参数的修剪:通过将它们设置为零来识别和消除大多数Delta参数(微调和预训练参数之间的差异)。...codellama/CodeLlama-7b-Instruct-hf parameters: density: 0.5 weight: 0.5 merge_method: ties
R ## R Function ## xicor <- function(X, Y, ties = TRUE){ n <- length(X) r <- rank(Y[order(X)], ties.method...= "random") set.seed(42) if(ties){ l <- rank(Y[order(X)], ties.method = "max") return( 1...) } } Python ## Python Function ## from numpy import array, random, arange def xicor(X, Y, ties...) n = len(X) order = array([i[0] for i in sorted(enumerate(X), key=lambda x: x[1])]) if ties...Julia ## Julia Function ## import Random function xicor(X::AbstractVector, Y::AbstractVector, ties
延伸阅读： （1）RANKX函数 RANKX(, , [ ], [ ], [ ]) RANKX 首先为table的每一行计值表达式...然后value在当前筛选上下文中计值，将得到的结果与列表中的值进行比较，根据排名规则order和ties的设置，返回最终排名。...ties: 可选，处理相同排名时的依据。skip 代表稀疏排名，下一名的排序等于之前所有排序的数量+1；dense 代表稠密排名，只累加排序，不考虑数量。默认使用 skip。
RankX ( , [, ] [, ] [, ] ) 位置 参数 描述 第1参数 Table 需要比对的表 第2参数 Expression...默认0 可选第5参数 Ties 碰到同排名，之后的排名是顺延排序Dense，还是跳过排序Skip。
persons, 1 buss, 1 handbags, Done. (0.011s) image 10/10 data/samples/zidane.jpg: 192x320 3 persons, 3 ties..., 1 skateboards, Done. (0.018s) image 10/10 data/samples/zidane.jpg: 320x512 3 persons, 2 ties, Done....stop signs, Done. (0.037s) image 9/10 data/samples/bus.jpg: 800x608 4 persons, 1 bicycles, 1 buss, 1 ties.../10 data/samples/24274813513_0cfd2ce6d0_k.jpg: 704x1024 14 persons, 1 cars, 1 trucks, 2 handbags, 2 ties..., 1 cups, Done. (0.078s) image 10/10 data/samples/zidane.jpg: 768x1280 2 ties, Done. (0.062s) Results
print('%s Wins, %s Losses, %s Ties' % (wins, losses, ties)) while True: # The player input loop....ties = ties + 1 elif playerMove == 'r' and computerMove == 's': print('You win!')...print('%s Wins, %s Losses, %s Ties' % (wins, losses, ties)) while True: # The player input loop....ties = ties + 1 elif playerMove == 'r' and computerMove == 's': print('You win!')...它还适当增加wins、losses或ties变量。一旦执行到达末尾，它就跳回到主程序循环的开始，开始另一个游戏。
xx.x.xx.xx:9092 --topic wangtest >this is a test message from wangwang >from itqunqi^H^H^H^H^H^[[3~ >Ties...xx.xx.xx.xx:9092 --topic wangtest --from-beginning this is a test message from wangwang from itqunqi Ties
following, sorted by descending frequency: the 4 is 3 sunny 2 day 1 Note: Don’t worry about handling ties
稳定化的 API array::each_ref 和 array::each_mut core::net f32::round_ties_even 和 f64::round_ties_even 一系列切片操作函数
'A man can never have too many ties.' 'And a woman can't have many hats.' she answered.
在这个应用中，我会写一个组件来跟踪输（losses）赢（wins）和平局（ties）的得分结果。...RESTful Java API应该以JSON格式返回以下结果： { "wins":"5", "losses":"3", "ties": "0"} 如果RESTful JavaScript客户端只对wins...因此，最好采取以下措施： www.mcnz.com/rps/score/wins → returns "5" looses和ties应该遵循类似的RESTful URL格式： www.mcnz.com/...rps/score/losses → returns "3" www.mcnz.com/rps/score/ties → returns "0" 正确的RESTful HTTP方法示例 到目前为止，所有
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