tree.js 获取子节点

// 假设我们有以下树结构数据
const treeData = {
  id: 1,
  name: 'Root',
  children: [
    {
      id: 2,
      name: 'Child 1',
      children: [
        { id: 3, name: 'Grandchild 1' },
        { id: 4, name: 'Grandchild 2' }
      ]
    },
    {
      id: 5,
      name: 'Child 2'
    }
  ]
};

// 使用 tree.js 获取指定节点的子节点
function getChildren(node) {
  return node.children || [];
}

const rootChildren = getChildren(treeData);
console.log(rootChildren); // 输出: [{ id: 2, name: 'Child 1', ... }, { id: 5, name: 'Child 2' }]

function getAllDescendants(node) {
  let descendants = [];
  if (node.children) {
    for (let child of node.children) {
      descendants.push(child);
      descendants = descendants.concat(getAllDescendants(child));
    }
  }
  return descendants;
}

const allDescendants = getAllDescendants(treeData);
console.log(allDescendants); // 输出: 所有子孙节点

function findNodeByProperty(node, property, value) {
  if (node[property] === value) {
    return node;
  }
  if (node.children) {
    for (let child of node.children) {
      const result = findNodeByProperty(child, property, value);
      if (result) return result;
    }
  }
  return null;
}

const foundNode = findNodeByProperty(treeData, 'name', 'Grandchild 1');
console.log(foundNode); // 输出: { id: 3, name: 'Grandchild 1' }