《Python编程：从入门到实践》组织列表课后习题：宴会名单

最近在看《Python编程：从入门到实践》一书，对零基础很友好，简单的做了一下习题，知识点很详细。

3-4 嘉宾名单 ：如果你可以邀请任何人一起共进晚餐（无论是在世的还是故去的），你会邀请哪些人？请创建一个列表，其中包含至少3个你想邀请的人；然后，使用这个列表打印消息，邀请这些人来与你共进晚餐。

names=['Sally','Jason','Doris','Aimee']

print(names[0]+"would you like to have dinner with me")

print(names[1]+"would you like to have dinner with me")

print(names[-1]+"would you like to have dinner with me")

print(names[-2]+"would you like to have dinner with me")

3-5 修改嘉宾名单 ：你刚得知有位嘉宾无法赴约，因此需要另外邀请一位嘉宾。

以完成练习3-4时编写的程序为基础，在程序末尾添加一条print 语句，指出哪位嘉宾无法赴约。

print(names[-1] + " can not come")

修改嘉宾名单，将无法赴约的嘉宾的姓名替换为新邀请的嘉宾的姓

names[-1] = 'Ark'

再次打印一系列消息，向名单中的每位嘉宾发出邀请。

print(names[0]+"would you like to have dinner with me")

print(names[1]+"would you like to have dinner with me")

print(names[-1]+"would you like to have dinner with me")

print(names[-2]+"would you like to have dinner with me")

3-6 添加嘉宾 ：你刚找到了一个更大的餐桌，可容纳更多的嘉宾。请想想你还想邀请哪三位嘉宾。

以完成练习3-4或练习3-5时编写的程序为基础，在程序末尾添加一条print 语句，指出你找到了一个更大的餐桌。

print('I find a bigger table.')

使用insert() 将一位新嘉宾添加到名单开头。

names.insert(0, 'O')

使用insert() 将另一位新嘉宾添加到名单中间。

name.insert(2,'L')

使用append() 将最后一位新嘉宾添加到名单末尾。

name.append('M')

打印一系列消息，向名单中的每位嘉宾发出邀请。

print(names[0]+ " would you like to have dinner with me?")

print(names[1]+ " would you like to have dinner with me?")

print(names[2]+ " would you like to have dinner with me?")

print(names[3]+ " would you like to have dinner with me?")

print(names[4]+ " would you like to have dinner with me?")

print(names[5]+ " would you like to have dinner with me?")

print(names[6]+ " would you like to have dinner with me?")

3-7 缩减名单 ：你刚得知新购买的餐桌无法及时送达，因此只能邀请两位嘉宾。

以完成练习3-6时编写的程序为基础，在程序末尾添加一行代码，打印一条你只能邀请两位嘉宾共进晚餐的消息。

print('The table can not arrive on time, so just two people can have dinner.')

使用pop() 不断地删除名单中的嘉宾，直到只有两位嘉宾为止。每次从名单中弹出一位嘉宾时，都打印一条消息，让该嘉宾知悉你很抱歉，无法邀请他来共进晚餐。

n1 = names.pop()

print(n1 + " sorry to tell you can not have dinner with me.")

n2 = names.pop()

print(n2 + " sorry to tell you can not have dinner with me.")

n3 = names.pop()

print(n3 + " sorry to tell you can not have dinner with me.")

n4 = names.pop()

print(n4 + " sorry to tell you can not have dinner with me.")

n5 = names.pop()

print(n5 + " sorry to tell you can not have dinner with me.")

对于余下的两位嘉宾中的每一位，都打印一条消息，指出他依然在受邀人之列。

print(names[0] + ", welcome to have dinner.")

print(names[1] + ", welcome to have dinner.")

使用del 将最后两位嘉宾从名单中删除，让名单变成空的。打印该名单，核实程序结束时名单确实是空的。

del names[0]

del names[0]

print(names)