std::bit_and
Defined in header <functional> | | |
|---|---|---|
template< class T > struct bit_and; | | (until C++14) |
template< class T = void > struct bit_and; | | (since C++14) |
函数对象，用于按位执行和。有效呼叫operator&论类型T...
专门性
The standard library provides a specialization of std::bit_and when T is not specified, which leaves the parameter types and return type to be deduced. bit_and<void> function object implementing x & y deducing argument and return types (class template specialization) | bit_and<void> | function object implementing x & y deducing argument and return types (class template specialization) | (since C++14) |
|---|---|---|---|
bit_and<void> | function object implementing x & y deducing argument and return types (class template specialization) |
成员类型
Type | Definition |
|---|---|
result_type(deprecated in C++17) | T |
first_argument_type(deprecated in C++17) | T |
second_argument_type(deprecated in C++17) | T |
成员函数
operator() | returns the result of bitwise AND of two arguments (public member function) |
|---|
STD：BIT[医]操作员%28%29
T operator()( const T& lhs, const T& rhs ) const; | | (until C++14) |
|---|---|---|
constexpr T operator()( const T& lhs, const T& rhs ) const; | | (since C++14) |
返回按位和lhs和rhs...
参数
lhs, rhs | - | values to compute bitwise AND of |
|---|
返回值
结果lhs & rhs...
例外
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可能的实施
ConstT算子%28%29%28 const T&lhs，const T&rhs%29 const{返回lhs&rhs；}
*。
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