前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >LWC 62:745. Prefix and Suffix Search

LWC 62:745. Prefix and Suffix Search

作者头像
用户1147447
发布2018-01-02 11:01:33
6440
发布2018-01-02 11:01:33
举报
文章被收录于专栏:机器学习入门

LWC 62:745. Prefix and Suffix Search

传送门:745. Prefix and Suffix Search

Problem:

Given many words, words[i] has weight i. Design a class WordFilter that supports one function, WordFilter.f(String prefix, String suffix). It will return the word with given prefix and suffix with maximum weight. If no word exists, return -1.

Examples:

Input: WordFilter([“apple”]) WordFilter.f(“a”, “e”) // returns 0 WordFilter.f(“b”, “”) // returns -1

Note:

words has length in range [1, 15000].

For each test case, up to words.length queries WordFilter.f may be made.

words[i] has length in range [1, 10].

prefix, suffix have lengths in range [0, 10].

words[i] and prefix, suffix queries consist of lowercase letters only.

思路: 此题不看效率的话有点水,追求效率的可以考虑Trie树,此处不考虑Trie优化。简单来说,每个word都有对应的prefix和suffix,所以 对于一个word生成所有prefix和suffix的组合,并更新当前组合的权值即可。时间复杂度为O(n^2)

Java版本:

代码语言:javascript
复制
public class WordFilter {

    Map<String, Integer> map;
    public WordFilter(String[] words) {
        map = new HashMap<>();
        for (int i = 0; i < words.length; ++i) {
            List<String> prefix = new ArrayList<>();
            List<String> suffix = new ArrayList<>();
            String word = words[i];
            for (int j = 0; j <= word.length(); ++j) {
                prefix.add(word.substring(0, j));
            }
            for (int j = word.length(); j >= 0; --j) {
                suffix.add(word.substring(j));
            }

            for (String pre : prefix) {
                for (String suf : suffix) {
                    if (!map.containsKey(pre + "#" + suf)) map.put(pre + "#" + suf, i);
                    else map.put(pre + "#" + suf, Math.max(map.get(pre + "#" + suf), i));
                }
            }
        }
    }

    public int f(String prefix, String suffix) {
        if (map.containsKey(prefix + "#" + suffix)) return map.get(prefix + "#" + suffix);
        return -1;
    }
}

Python版本:

代码语言:javascript
复制
class WordFilter(object):

    def __init__(self, words):
        """
        :type words: List[str]
        """
        self.map = {}
        for index, word in enumerate(words):
            prefix = ''
            for char in [''] + list(word):
                prefix += char
                suffix = ''
                for char in [''] + list(word[::-1]):
                    suffix += char
                    self.map[prefix + '#' + suffix[::-1]] = index


    def f(self, prefix, suffix):
        """
        :type prefix: str
        :type suffix: str
        :rtype: int
        """
        return self.map.get(prefix + '#' + suffix, -1)

不得不说,python的代码比java精简优雅很多。

本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2017-12-10 ,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • LWC 62:745. Prefix and Suffix Search
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档