2.7版本以上直接用format设置千分位分隔符
Python 2.7 (r27:82500, Nov 23 2010, 18:07:12)
[GCC 4.1.2 20070115 (prerelease) (SUSE Linux)] on linux2
Type "help", "copyright", "credits" or "license" for more information.
>>> format(1234567890,',')
'1,234,567,890'
>>> print 'The value is {:0,.2f}'.format(1234567.125)
The value is 1,234,567.12
>>> print 'The value is {:0,.2f}'.format(1234567.126)
The value is 1,234,567.13
import re
def strConv(s):
s = str(s)
while True:
(s,count) = re.subn(r"(\d)(\d{3})((:?,\d\d\d)*)$",r"\1,\2\3",s)
if count == 0 : break
return s
print strConv(12345)
def number_format(num, places=0):
"""Format a number according to locality and given places"""
locale.setlocale(locale.LC_ALL, "")
return locale.format("%.*f", (places, num), True)
>>> import locale
>>> number_format(12345678.123)
'12,345,678'
>>> number_format(12345678.123, 2)
'12,345,678.12'
>>> import locale
>>> a = {'size': 123456789, 'unit': 'bytes'}
>>> print(locale.format("%(size).2f", a, 1))
123456789.00
>>> locale.setlocale(locale.LC_ALL, '') # Set the locale for your system
'en_US.UTF-8'
>>> print(locale.format("%(size).2f", a, 1))
123,456,789.00
>>> s = "1234567890"
>>> s = s[::-1]
>>> a = [s[i:i+3] for i in range(0,len(s),3)]
>>> print (",".join(a))[::-1]
perl -e '$size = "1234567890";while($size =~ s/(\d)(\d{3})((:?,\d\d\d)*)$/$1,$2$3/){};print $size, "\n";'
1,234,567,890
echo 12345|sed -e :a -e 's/\(.*[0-9]\)\([0-9]\{3\}\)/\1,\2/;ta'
12,345
printf "%'d\n" 12345
12,345
parseInt('123456789456.34').toLocaleString()
"123,456,789,456"
Intl.NumberFormat().format(1234.1235);
"1,234.124"
function addCommas(n){
var rx= /(\d+)(\d{3})/;
return String(n).replace(/^\d+/, function(w){
while(rx.test(w)){
w= w.replace(rx, '$1,$2');
}
return w;
});
}
addCommas('123456789456.34');
"123,456,789,456.34"
'12345678.34'.toString().replace(/\B(?=(\d{3})+(?!\d))/g, ",")
"12,345,678.34"
注:某些方法不支持小数部分或者小数部分四舍五入,请慎用。
[1] shell、perl、python 千分位 逗号分隔符输出
http://wenzhang.baidu.com/page/view?key=4f73729cefd8af8c-1426633956
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