元宵快乐：看SQL大师们用SQL绘制的团圆

数据和云

发布于 2018-03-05 14:42:35

9110

发布于 2018-03-05 14:42:35

文章被收录于专栏：数据和云

题记：在多年以前，论坛活跃的时代，在ITPUB上你能看到各种新奇有趣的知识，及时新鲜的信息，出类拔萃的技巧，有很多让人多年以后还记忆犹新。

这个帖子让我忍不住在这个日子，再次发送出来，让大家一起再次体会SQL的强大和神奇能力。而写好SQL，仍然是我们持续不断的追求。

话团圆，画团圆，元宵佳节倍思亲，可是大家知道吗，万能的SQL可以帮助大家绘制团圆。

在ITPUB论坛里，一群SQL爱好者们会用SQL来描摹一切可能。请看如下这段SQL，为大家绘制了团团圆圆的五连环：

with a as (select distinct round(a.x + b.x) x,round(a.y + b.y) y from
(select (sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n, cos(n/30 * 3.1415926)*2  x,
                           sin(n/30 * 3.1415926) y
                           from (select rownum - 1 n from all_objects where rownum <= 30 +30))) a,
            (select n, (sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n,
                           cos( m /3 * 3.1415926) * 2 * 15 x,
                           sin( m /3 * 3.1415926)* 15 y
                      from (select case when rownum <= 2 then 3 
                      when rownum = 3 then -2 else -6 end m, rownum - 1 n
                              from all_objects where rownum <= 5))) b
          )
select replace(sys_connect_by_path(point, '/'), '/', null) star
  from (select b.y, b.x, decode(a.x, null, ' ', '*') point
          from a,
               (select *
                  from (select rownum - 1 + (select min(x) from a) x
                          from all_objects
                         where rownum <= (select max(x) - min(x) + 1 from a)),
                       (select rownum - 1 + (select min(y) from a) y
                          from all_objects
                         where rownum <= (select max(y) - min(y) + 1 from a))) b
         where a.x(+) = b.x
           and a.y(+) = b.y)
where x = (select max(x) from a)
start with x = (select min(x) from a)
connect by y = prior y
       and x = prior x + 1;

这段SQL在Oracle中输出了下图，请用SQL执行：

好吧，这是五个连环，事实上是奥运会的五环旗，在庆祝奥运期间，网友 nyfor 的随手创作。

再看如下一段SQL，则是输出了一个五角星：

with a as (
            select distinct round(sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n,
                           cos(trunc(n / 20) * (1-1/5) * 3.1415926) * 2 x,
                           sin(trunc(n / 20) * (1-1/5) * 3.1415926) y
                      from (select rownum - 1 n from all_objects where rownum <= 20 * 5))
          )
select replace(sys_connect_by_path(point, '/'), '/', null) star
  from (select b.y, b.x, decode(a.x, null, ' ', '*') point
          from a,
               (select *
                  from (select rownum - 1 + (select min(x) from a) x
                          from all_objects
                         where rownum <= (select max(x) - min(x) + 1 from a)),
                       (select rownum - 1 + (select min(y) from a) y
                          from all_objects
                         where rownum <= (select max(y) - min(y) + 1 from a))) b
         where a.x(+) = b.x
           and a.y(+) = b.y)
where x = (select max(x) from a)
start with x = (select min(x) from a)
connect by y = prior y
       and x = prior x + 1;

这个SQL的解释如下：

其中数字20表示五角星每一条边上的点的个数(你也可以设置的大一些或小一些), 其中的数字5表示五角星的边数, 其中的数字2是为了调整横向字符间距与纵向行距之间的差异而设置的, 你也可以不乘以这个2, 这里只是为了输出稍微好看一些.

调整期中数字5, 你还可以输出7角星, 9角星.... 注意我的SQL不能输出6角星,8角星，因为我的SQL算法中是以一笔画能够画成的星为基础设计的算法的.

比如，以下是7角形输出：

在一轮讨论之后，newkid 大神给出了一个系列的SQL改写，小编就列举如下。

SQL一：

with a as ( select distinct round(sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n,
                           cos(trunc(n / 20) * (1-1/5) * 3.1415926) * 2 x,
                           sin(trunc(n / 20) * (1-1/5) * 3.1415926) y
                      from (select rownum - 1 n from DUAL CONNECT BY rownum <= 20 * 5))
          )
SELECT LPAD(REPLACE(SUM(POWER(10,x-1)),'0',' '),(SELECT MAX(x) FROM a)) AS star
  FROM a
GROUP BY y
ORDER BY y;

SQL二：

with a as ( select distinct round(sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n,
                           cos(trunc(n / 20) * (1-1/5) * 3.1415926) x,
                           sin(trunc(n / 20) * (1-1/5) * 3.1415926) y
                      from (select rownum - 1 n from DUAL CONNECT BY rownum <= 20 * 5))
          )
SELECT LPAD(REPLACE(SUM(POWER(10,x)),'0',' '),(SELECT MAX(x)+1 FROM a)) AS star
  FROM a
GROUP BY y
ORDER BY y;

SQL三：

with a as ( select distinct round(sum(x) over(order by n)) x,
                            round(sum(y) over(order by n)) y
              from (select n,
                           cos(trunc(n / 20) * (1-1/5) * 3.1415926) * 2 x,
                           sin(trunc(n / 20) * (1-1/5) * 3.1415926) y
                      from (select rownum - 1 n from DUAL CONNECT BY rownum <= 20 * 5))
          )
SELECT TRANSLATE(LPAD(NVL(SUM(POWER(10,CASE WHEN x>=40 THEN x-40 END)),0),(SELECT MAX(x)-39 FROM a WHERE x>=40))
                 ||LPAD(SUM(POWER(10,CASE WHEN x<40 THEN x END)),40) 
                ,'01',' *'
                )
        AS star
  FROM a
GROUP BY y
ORDER BY y;

SQL四：

with a as (SELECT x,y
                 ,ROW_NUMBER() OVER(PARTITION BY y ORDER BY x) rn
                 ,MAX(x) OVER(PARTITION BY y) maxx
             FROM (select distinct round(sum(x) over(order by n)) x,
                                  round(sum(y) over(order by n)) y
                    from (select n,
                                 cos(trunc(n / 20) * (1-1/5) * 3.1415926) * 2 x,
                                 sin(trunc(n / 20) * (1-1/5) * 3.1415926) y
                            from (select rownum - 1 n from DUAL CONNECT BY rownum <= 20 * 5)
                          )
                   )
          )
,t(rn,x,y,str,maxx) AS (
SELECT 1,x,y,LPAD('*',x+1),maxx FROM a WHERE rn=1
UNION ALL
SELECT a.rn,a.x,t.y,str||RPAD(' ',a.x-t.x-1)||'*',t.maxx
  FROM t,a 
WHERE t.rn=a.rn-1 AND t.y=a.y
) CYCLE x,y SET cycle_flag TO 'Y' DEFAULT 'N'
SELECT str FROM t WHERE x=maxx ORDER BY y;

SQL五：

VAR SCALE NUMBER;
EXEC :SCALE :=3;


with a as (SELECT x,y
                 ,ROW_NUMBER() OVER(PARTITION BY y ORDER BY x) rn
                 ,MAX(x) OVER(PARTITION BY y) maxx
             FROM (select distinct round(sum(x) over(order by n)) x,
                                  round(sum(y) over(order by n)) y
                    from (select n,
                                 cos(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) * 2 x,
                                 sin(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) y
                            from (select rownum - 1 n from DUAL CONNECT BY rownum <= 10*:SCALE * 5)
                          )
                   )
          )
,t(rn,x,y,str,maxx) AS (
SELECT 1,x,y,LPAD('*',x+1),maxx FROM a WHERE rn=1
UNION ALL
SELECT a.rn,a.x,t.y,str||RPAD(' ',a.x-t.x-1)||'*',t.maxx
  FROM t,a 
WHERE t.rn=a.rn-1 AND t.y=a.y
) CYCLE x,y SET cycle_flag TO 'Y' DEFAULT 'N'
SELECT str FROM t WHERE x=maxx ORDER BY y;

SQL六 - 利用wmsys.wm_concat的写法其实更简单：

with a as (SELECT x,y
                 ,LAG(x,1,0) OVER(PARTITION BY y ORDER BY x) last_x
             FROM (select distinct round(sum(x) over(order by n)) x,
                                  round(sum(y) over(order by n)) y
                    from (select n,
                                 cos(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) * 2 x,
                                 sin(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) y
                            from (select rownum - 1 n from DUAL CONNECT BY rownum <= 10*:SCALE * 5)
                          )
                   )
          )
SELECT REPLACE(MAX(str),',') STR
  FROM (SELECT y,wmsys.wm_concat(LPAD('*',x-last_x)) OVER(PARTITION BY y ORDER BY x) str
          FROM a
        )
GROUP BY y
ORDER BY y;

SQL之七 - wmsys.wm_concat的connect by替代写法：

with a as (SELECT x,y
                 ,LAG(x,1,0) OVER(PARTITION BY y ORDER BY x) last_x
                 ,ROW_NUMBER() OVER(PARTITION BY y ORDER BY x) rn
             FROM (select distinct round(sum(x) over(order by n)) x,
                                  round(sum(y) over(order by n)) y
                    from (select n,
                                 cos(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) * 2 x,
                                 sin(trunc(n / (10*:SCALE)) * (1-1/5) * 3.1415926) y
                            from (select rownum - 1 n from DUAL CONNECT BY rownum <= 10*:SCALE * 5)
                          )
                   )
          )
SELECT REPLACE(MAX(str),',') STR
  FROM (SELECT y,SYS_CONNECT_BY_PATH(LPAD('*',x-last_x),',') str
          FROM a
         START WITH rn=1
        CONNECT BY y=PRIOR y AND rn=PRIOR rn+1
        )
GROUP BY y
ORDER BY y;

SQL如神，学习入化，动手为王，祝愿大家元宵节快乐！

还有一些神奇的文章：

无往不利：用SQL解海盗分金的利益最大化问题

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122ARCH，Oracle 12.2 体系结构图

2017OOW，Oracle OpenWorld 资料

PRELECTION，大讲堂讲师课程资料

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原始发表：2018-03-01，如有侵权请联系 cloudcommunity@tencent.com 删除

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