下面分享大牛一道题的两种(递归+非递归)的解法,供大家学习!也欢迎贡献你的题解!
原题链接:发工资咯 http://www.dotcpp.com/oj/problem1197.html
解题思路: 1.要为所有员工工资准备的钱的张数最少,则发给每个员工的工资里钱的张数要最少;
2.要发给每个员工的工资里钱的张数要最少,则要先发面值最大的钱,再发次大的,再发次次大的;
3.假设某员工薪水为121;(则有以下递归关系)
(1):薪水大于100,先发给面值为100的钱,所发张数为:121/100=1张......21元;(还需发21元)
(2):21>大于10,小于50,故发面值为10的钱,所发张数为:21/10=2张......1元;(还需发1元)
(3):1等于1,故发面值为1的钱,所发张数为:1/1=1张......0元;
4.1张+2张+1张=4张 :即该员工所需最少的钱的张数为4张;
6.求出每个员工所需张数再加起来,就是总的所需最少张数;
参考代码:
#include <stdio.h>
void fun_ction( int salary, int *Count );
int main()
{
int num_ofpeople;
int salary;
int Count;
while ( scanf( "%d", &num_ofpeople ) != EOF && num_ofpeople != 0 )
{ //因为之前有题目以0结束,但是提交输出超限,加上EOF正确,所以这里也加了一个以文件结束符结束避免出错
Count = 0;
for ( int i = 0; i < num_ofpeople; i++ )
{
scanf( "%d", &salary );
fun_ction( salary, &Count );
}
printf( "%d\n", Count );
}
return(0);
}
/*---------------------------------------------------------------*/
void fun_ction( int salary, int *Count )
{
if ( salary == 0 )//发完返回
return;
if ( salary == 1 )
{//直接加1,并返回,不用再递归到:fun_ction(salary%1,Count);
(*Count)++; return;
}else
if ( salary >= 2 && salary < 5 )
{
(*Count) += (salary / 2);
fun_ction( salary % 2, Count );
}else
if ( salary >= 5 && salary < 10 )
{
(*Count) += (salary / 5);
fun_ction( salary % 5, Count );
}else
if ( salary >= 10 && salary < 50 )
{
(*Count) += (salary / 10);
fun_ction( salary % 10, Count );
}else
if ( salary >= 50 && salary < 100 )
{
(*Count) += (salary / 50);
fun_ction( salary % 50, Count );
}else
if ( salary >= 100 )
{
(*Count) += (salary / 100);
fun_ction( salary % 100, Count );
}
return;
}
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非递归
(在使用非递归方法的时候,每个if条件之间不能用else连接,因为上一个if中salary改变后的值,要作为后面的判断条件,加了else的话,执行一个后,其后面的就都不执行了。)
#include <stdio.h>
void fun_ction( int salary, int *Count );
int main()
{
int num_ofpeople;
int salary;
int Count;
while ( scanf( "%d", &num_ofpeople ) != EOF && num_ofpeople != 0 )
{
Count = 0;
for ( int i = 0; i < num_ofpeople; i++ )
{
scanf( "%d", &salary );
fun_ction( salary, &Count );
}
printf( "%d\n", Count );
}
return(0);
}
/*---------------------------------------------------------------*/
void fun_ction( int salary, int *Count )
{
if ( salary >= 100 )
{
(*Count) += (salary / 100);
salary%=100;
}
if ( salary >= 50 && salary < 100 )
{
(*Count) += (salary / 50);
salary%=50;
}
if ( salary >= 10 && salary < 50 )
{
(*Count) += (salary / 10);
salary%=10;
}
if ( salary >= 5 && salary < 10 )
{
(*Count) += (salary / 5);
salary%=5;
}
if ( salary >= 2 && salary < 5 )
{
(*Count) += (salary / 2);
salary%=2;
}
if ( salary == 1 )
{
(*Count)++;
}
return;
}
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