Say you have an array for which the ith element is the price of a given stock on day i.
Design an algorithm to find the maximum profit. You may complete as many transactions as you like (ie, buy one and sell one share of the stock multiple times). However, you may not engage in multiple transactions at the same time (ie, you must sell the stock before you buy again).
题目参考 Q121
这题是可以多次买入多次卖出,但是比 Q121 还要简单。只要一涨价,就卖出即可。
class Solution:
def maxProfit(self, prices):
"""
:type prices: List[int]
:rtype: int
"""
maxP = 0 # 最大利润
for i in range(len(prices) - 1):
if prices[i] < prices[i+1]: # 涨价就卖出,同时累加利润
maxP += prices[i+1] - prices[i]
return maxP
a = [7,2,5,3,6,4,1,5,6,4,0]
b = Solution()
print(b.maxProfit(a)) # 11 # (2->5) + (3->6) + (1->5) + (5->6)