Table t has 2 columns: id INT; value CHAR(1); Column id starts from 0, increased by 1 each row Column value is a single character string Table t has at least 1 row String s is a palindrome when: s[i] = s[s.length - i - 1] for i = 0 … (s.length – 1) / 2 E.g.: a, aba, abba. Q: Write one SQL statement to check if the string composed of value of t ordered by id is a palindrome (case sensitive). Output “Y” or “N”.
with tmp as ( (select (select count(1) from t1)-1-id as id,value from t1) except (select id,value from t1) ) select case when count(1)=0 then 'Y' else 'N' end from tmp;