前往小程序,Get更优阅读体验!
立即前往
首页
学习
活动
专区
工具
TVP
发布
社区首页 >专栏 >两数之和 (一)

两数之和 (一)

作者头像
努力在北京混出人样
发布2019-02-18 15:39:25
4270
发布2019-02-18 15:39:25
举报
文章被收录于专栏:祥子的故事祥子的故事

题目:

给定一个整型数组,是否能找出其中的两个数使其和为某个指定的值?

注意:这里对数据没有限制,表明数据中允许存在重复值 伪代码:

代码语言:javascript
复制
boolean hasSum(int[] A, int target){ 
    boolean res = false;
    if(A ==null || A.length<2) return res;
    Arrays.sort(A);
    int i =0,j=A.length-1;
    while (i <j){
        if(A[i]+A[j] == target){
            res = true;
            break;
        }else if (A[i]+A[j] > target){
            //目标值过小,则向前移动尾部指针,减小两数之和;
            j--;
        }else{
            //目标值过大,则向后移动首部指针,增加两数和;
            i++;
        }
   }
   return res;

}

有了这个伪代码,代码就好写。下面用R语言和python写:

R语言

代码语言:javascript
复制
> a= c(1:10,2:11,1:3,2:8,2:9)

> res = list()
> index = list()

> aa = function(a,target=NULL)
{
  if (length(a) < 2)
  {
    return (res)
  }
  a1 = sort(a);
  i = 1;j=length(a);k=0;
  while(i < j)
  {
    if (a1[i]+a1[j] == target)
    {
      k=k+1;
      res[[k]] = c(a1[i],a1[j]);
      index[[k]] = append(res[[k]],c(i,j));
      i = i +1;
      j = j -1;
    }
    else if (a1[i]+a1[j]>target)
    {
      j = j -1;
    }
    else
    {
      i = i +1;
    }
  }
  return (index)
}

> aa(a,6)
[[1]]
[1]  1  5  1 20

[[2]]
[1]  1  5  2 19

[[3]]
[1]  2  4  3 16

[[4]]
[1]  2  4  4 15

[[5]]
[1]  2  4  5 14

[[6]]
[1]  2  4  6 13

[[7]]
[1]  3  3  8 12

[[8]]
[1]  3  3  9 11

得到了等于6的两个数,还得到了在排序后它们的位置。

python

1、暴力法

代码语言:javascript
复制
# -*- coding: utf-8 -*-
a = [1,2,3,4,2,1,2,3,4,5,6,4,5,6,4,3,2,2,1,3,4,5,6,7,8,5,4,3,2,1]
len1 = len(a)
target = 6
#number = map(int,a)
for i in range(len1):
    for j in range(i+1,len1):
        if a[i] + a[j] == target:
              print "the two number are %d and  %d ,the index are %d and %d " % (a[i],a[j],i+1,j+1)

the two number are 1 and  5 ,the index are 1 and 10 
the two number are 1 and  5 ,the index are 1 and 13 
the two number are 1 and  5 ,the index are 1 and 22 
the two number are 1 and  5 ,the index are 1 and 26 
the two number are 2 and  4 ,the index are 2 and 4 
the two number are 2 and  4 ,the index are 2 and 9 
the two number are 2 and  4 ,the index are 2 and 12 
the two number are 2 and  4 ,the index are 2 and 15 
the two number are 2 and  4 ,the index are 2 and 21 
the two number are 2 and  4 ,the index are 2 and 27 
the two number are 3 and  3 ,the index are 3 and 8 
the two number are 3 and  3 ,the index are 3 and 16 
the two number are 3 and  3 ,the index are 3 and 20 
the two number are 3 and  3 ,the index are 3 and 28 
the two number are 4 and  2 ,the index are 4 and 5 
the two number are 4 and  2 ,the index are 4 and 7 
the two number are 4 and  2 ,the index are 4 and 17 
the two number are 4 and  2 ,the index are 4 and 18 
the two number are 4 and  2 ,the index are 4 and 29 
the two number are 2 and  4 ,the index are 5 and 9 
the two number are 2 and  4 ,the index are 5 and 12 
the two number are 2 and  4 ,the index are 5 and 15 
the two number are 2 and  4 ,the index are 5 and 21 
the two number are 2 and  4 ,the index are 5 and 27 
the two number are 1 and  5 ,the index are 6 and 10 
the two number are 1 and  5 ,the index are 6 and 13 
the two number are 1 and  5 ,the index are 6 and 22 
the two number are 1 and  5 ,the index are 6 and 26 
the two number are 2 and  4 ,the index are 7 and 9 
the two number are 2 and  4 ,the index are 7 and 12 
the two number are 2 and  4 ,the index are 7 and 15 
the two number are 2 and  4 ,the index are 7 and 21 
the two number are 2 and  4 ,the index are 7 and 27 
the two number are 3 and  3 ,the index are 8 and 16 
the two number are 3 and  3 ,the index are 8 and 20 
the two number are 3 and  3 ,the index are 8 and 28 
the two number are 4 and  2 ,the index are 9 and 17 
the two number are 4 and  2 ,the index are 9 and 18 
the two number are 4 and  2 ,the index are 9 and 29 
the two number are 5 and  1 ,the index are 10 and 19 
the two number are 5 and  1 ,the index are 10 and 30 
the two number are 4 and  2 ,the index are 12 and 17 
the two number are 4 and  2 ,the index are 12 and 18 
the two number are 4 and  2 ,the index are 12 and 29 
the two number are 5 and  1 ,the index are 13 and 19 
the two number are 5 and  1 ,the index are 13 and 30 
the two number are 4 and  2 ,the index are 15 and 17 
the two number are 4 and  2 ,the index are 15 and 18 
the two number are 4 and  2 ,the index are 15 and 29 
the two number are 3 and  3 ,the index are 16 and 20 
the two number are 3 and  3 ,the index are 16 and 28 
the two number are 2 and  4 ,the index are 17 and 21 
the two number are 2 and  4 ,the index are 17 and 27 
the two number are 2 and  4 ,the index are 18 and 21 
the two number are 2 and  4 ,the index are 18 and 27 
the two number are 1 and  5 ,the index are 19 and 22 
the two number are 1 and  5 ,the index are 19 and 26 
the two number are 3 and  3 ,the index are 20 and 28 
the two number are 4 and  2 ,the index are 21 and 29 
the two number are 5 and  1 ,the index are 22 and 30 
the two number are 5 and  1 ,the index are 26 and 30 
the two number are 4 and  2 ,the index are 27 and 29

暴力法复杂度较高,下面做下修改:

代码语言:javascript
复制
# -*- coding: utf-8 -*-
res = []
def sum_two_1(a,target):
    if (len(a) < 2):
        return (0)
    a1 =sorted(a)
    i=0;j=len(a1)-1;k=0;
    while(i<j):
        if (a1[i]+a1[j] == target):
            k=k+1
            res.append([a1[i],a1[j],[i,j]])
            i = i + 1
            j = j -1
        elif(a1[i]+a1[j] > target):
            j = j -1
        else:
            i = i +1
    return(res)

if __name__ == "__main__":
    a = [1,2,3,4,2,1,2,3,4,5,6,4,5,6,4,3,2,2,1,3,4,5,6,7,8,5,4,3,2,1]
    print(sum_two_1(a,int(4)))

[[1, 3, [0, 14]], [1, 3, [1, 13]], [1, 3, [2, 12]], [1, 3, [3, 11]], [2, 2, [4, 9]], [2, 2, [5, 8]], [2, 2, [6, 7]]]

在python中能否改为字典呢?

本文参与 腾讯云自媒体分享计划,分享自作者个人站点/博客。
原始发表:2016年12月01日,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体分享计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • R语言
  • python
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档