SQL题目50道持续更新

lop

发布于 2019-03-13 16:51:35

8490

发布于 2019-03-13 16:51:35

文章被收录于专栏：小六

数据如下,我在答题过程中使用的是mysql数据库

create table Student
(
  S     varchar(10),
  Sname nvarchar(10),
  Sage  datetime,
  Ssex  nvarchar(10)
);
insert into Student
values ('01', N'赵雷', '1990-01-01', N'男');
insert into Student
values ('02', N'钱电', '1990-12-21', N'男');
insert into Student
values ('03', N'孙风', '1990-05-20', N'男');
insert into Student
values ('04', N'李云', '1990-08-06', N'男');
insert into Student
values ('05', N'周梅', '1991-12-01', N'女');
insert into Student
values ('06', N'吴兰', '1992-03-01', N'女');
insert into Student
values ('07', N'郑竹', '1989-07-01', N'女');
insert into Student
values ('08', N'王菊', '1990-01-20', N'女');



create table Course
(
  C     varchar(10),
  Cname nvarchar(10),
  T     varchar(10)
);
insert into Course
values ('01', N'语文', '02');
insert into Course
values ('02', N'数学', '01');
insert into Course
values ('03', N'英语', '03');


create table Teacher
(
  T     varchar(10),
  Tname nvarchar(10)
);
insert into Teacher
values ('01', N'张三');
insert into Teacher
values ('02', N'李四');
insert into Teacher
values ('03', N'王五');


create table SC
(
  S     varchar(10),
  C     varchar(10),
  score decimal(18, 1)
);
insert into SC
values ('01', '01', 80);
insert into SC
values ('01', '02', 90);
insert into SC
values ('01', '03', 99);
insert into SC
values ('02', '01', 70);
insert into SC
values ('02', '02', 60);
insert into SC
values ('02', '03', 80);
insert into SC
values ('03', '01', 80);
insert into SC
values ('03', '02', 80);
insert into SC
values ('03', '03', 80);
insert into SC
values ('04', '01', 50);
insert into SC
values ('04', '02', 30);
insert into SC
values ('04', '03', 20);
insert into SC
values ('05', '01', 76);
insert into SC
values ('05', '02', 87);
insert into SC
values ('06', '01', 31);
insert into SC
values ('06', '03', 34);
insert into SC
values ('07', '02', 89);
insert into SC
values ('07', '03', 98);

insert into SC
values ('07', '04', 98);

有些题目可能会有不对的sql,是在写题目的时候打得

# 1. 查询" 01 "课程比" 02 "课程成绩高的学生的信息及课程分数

SELECT Student.S,Sname,Sage, Ssex,C,score_01,score_02
FROM Student
       JOIN (
  SELECT *
  FROM (SELECT S,C,score score_01 FROM SC WHERE C = '01') a
         LEFT JOIN (SELECT S new_s, C new_c, score score_02 FROM SC WHERE C = '02') b ON a.S = b.new_s
  WHERE a.score_01 > b.score_02) c ON Student.S = c.new_s;


# 1.1 查询同时存在" 01 "课程和" 02 "课程的情况

SELECT *
FROM (SELECT * FROM SC WHERE C = '01') a
       JOIN (SELECT * FROM SC WHERE C = '02') b ON a.S = b.S;


# 1.2 查询存在" 01 "课程但可能不存在" 02 "课程的情况(不存在时显示为 null )

SELECT *
FROM (SELECT * FROM SC WHERE C = '01') a
       LEFT JOIN (SELECT * FROM SC WHERE C = '02') b ON a.S = b.S;


# 1.3 查询选课不存在" 01 "课程但存在" 02 "课程的情况

# 解法1
SELECT *
FROM SC
WHERE C = '02'
  AND S NOT IN (SELECT S
                FROM SC
                WHERE C = '01');

# 解法2
SELECT *
FROM SC A
WHERE A.C = '02'
  AND NOT EXISTS
  (SELECT S
   FROM SC B
   WHERE A.S = B.S
     AND C = '01');


# 解法3
SELECT *
FROM (SELECT * FROM SC WHERE C = '01') a
       LEFT JOIN (SELECT * FROM SC WHERE C = '02') b ON a.S = b.S;


# 2. 查询平均成绩大于等于 60 分的同学的学生编号和学生姓名和平均成绩

SELECT A.S,B.Sname,A.dc
FROM (SELECT S,AVG(score) dc FROM SC GROUP BY S HAVING AVG(score) > 60) A
       LEFT JOIN Student B ON A.S = B.S;


# 3. 查询在 SC 表存在成绩的学生信息

SELECT *
FROM Student
WHERE EXISTS(SELECT * FROM SC where SC.S = Student.S);


# 4. 查询所有同学的学生编号、学生姓名、选课总数、所有课程的总成绩(没成绩的显示为 null )

SELECT Student.S, Student.Sname, 选课总数, 总成绩
FROM (SELECT S, count(C) 选课总数, sum(score) 总成绩 FROM SC GROUP BY S) A
       RIGHT JOIN Student ON Student.S = A.S;


# 4.1 查有成绩的学生信息

SELECT Student.S, Student.Sname, 选课总数, 总成绩
FROM (SELECT S, count(C) 选课总数, sum(score) 总成绩 FROM SC GROUP BY S) A
       LEFT JOIN Student ON Student.S = A.S;


# 5. 查询「李」姓老师的数量 

SELECT COUNT(*)
FROM Teacher
where Tname LIKE '李%';


# 6. 查询学过「张三」老师授课的同学的信息 

SELECT *
FROM Student
WHERE EXISTS(SELECT *
             FROM SC
             WHERE Student.S = SC.S
               AND EXISTS(SELECT *
                          FROM Course
                          WHERE SC.C = Course.C
                            AND EXISTS(SELECT *
                                       FROM Teacher
                                       WHERE Teacher.Tname = '张三'
                                         AND Course.T = Teacher.T)
               ));

# 7. 查询没有学全所有课程的同学的信息 

# 解法1
SELECT *
FROM Student
WHERE S NOT IN (SELECT S FROM SC GROUP BY S HAVING COUNT(C) = (SELECT COUNT(*) FROM Course));

# 解法2
SELECT *
FROM Student
WHERE NOT EXISTS(
    SELECT S
    FROM SC
    WHERE SC.S = Student.S
    GROUP BY SC.S
    HAVING COUNT(*) = (SELECT COUNT(*) FROM Course)
  );


# 8. 查询至少有一门课与学号为" 01 "的同学所学相同的同学的信息 

# 解法1
SELECT *
FROM Student
WHERE S IN (SELECT S
            FROM SC
            WHERE C IN (
              SELECT DISTINCT C
              FROM SC
              WHERE S = '01'
            ));

# 解法2
SELECT *
FROM Student
WHERE EXISTS(
          SELECT *
          FROM SC A
          WHERE A.S = Student.S
            AND EXISTS(
              SELECT *
              FROM SC B
              WHERE A.C = B.C
                AND B.S = '01'
            ));


# 9. 查询和" 01 "号的同学学习的课程完全相同的其他同学的信息 

# 解法1 先把找出选修了其他课程的人, 将其过滤, 然后分组统计


SELECT *
FROM Student C
WHERE EXISTS(
          SELECT A.S
          FROM SC A
          WHERE C.S = A.S
            AND EXISTS(SELECT * FROM SC B WHERE A.C = B.C AND B.S = '01')
          GROUP BY A.S
          HAVING COUNT(*) = (SELECT COUNT(*) FROM SC WHERE S = '01'));


SELECT *
FROM Student a
WHERE NOT EXISTS
  (SELECT *
   FROM SC b
   WHERE S = '01'
     AND NOT EXISTS
     (SELECT * FROM SC c WHERE c.S = a.S AND c.C = b.C));


# 解法2
SELECT *
FROM Student
WHERE EXISTS(SELECT A.S
             FROM SC A
                    JOIN (SELECT C FROM SC WHERE S = '01') B ON A.C = B.C
             WHERE Student.S = A.S
             GROUP BY A.S
             HAVING COUNT(*) = (SELECT COUNT(*) FROM SC WHERE S = '01'));


# 10. 查询没学过"张三"老师讲授的任一门课程的学生姓名 

SELECT Sname
FROM Student s
WHERE NOT EXISTS(
    SELECT *
    FROM SC sc
    WHERE s.S = sc.S
      AND EXISTS(
        SELECT *
        FROM Course c
        WHERE sc.C = c.C
          AND EXISTS(
            SELECT *
            FROM Teacher t
            WHERE c.T = t.T
              AND t.Tname = '张三'
          )));


# 11. 查询两门及其以上不及格课程的同学的学号，姓名及其平均成绩 

SELECT *
FROM Student
WHERE EXISTS(SELECT S
             FROM SC
             WHERE Student.S = SC.S
             GROUP BY S
             HAVING SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) >= 2);

SELECT Student.S,Student.Sname,avg
FROM Student
       JOIN (SELECT S,avg(score) avg
             FROM SC
             GROUP BY S
             HAVING SUM(CASE WHEN score < 60 THEN 1 ELSE 0 END) >= 2) B ON Student.S = B.S;


# 12. 检索" 01 "课程分数小于 60学生信息，按分数降序排列的学生信息

SELECT *
FROM Student
       JOIN (SELECT *
             FROM SC
             WHERE SC.score < 60
) B ON Student.S = B.S
ORDER BY score DESC;


# 13. 按平均成绩从高到低显示所有学生的所有课程的成绩以及平均成绩

SELECT S,
       MAX(CASE C WHEN '01' THEN score ELSE 0 END) '01',
       MAX(CASE C WHEN '02' THEN score ELSE 0 END) '02',
       MAX(CASE C WHEN '03' THEN score ELSE 0 END) '03',
       AVG(score)                                  平均分
FROM SC
GROUP BY S
ORDER BY 平均分 DESC;

# 14. 查询各科成绩最高分、最低分和平均分：
#     以如下形式显示：课程 ID，课程 name，最高分，最低分，平均分，及格率，中等率，优良率，优秀率
#     及格为>=60，中等为：70-80，优良为：80-90，优秀为：>=90
#     要求输出课程号和选修人数，查询结果按人数降序排列，若人数相同，按课程号升序排列

SELECT ID,
       Cname,
       选修人数,
       最高分,
       最低分,
       平均分,
       及格率,
       中等率,
       优良率,
       优秀率
FROM Course
       JOIN (SELECT C                                                                            ID,
                    COUNT(*)                                                                     选修人数,
                    MAX(score)                                                                   最高分,
                    MIN(score)                                                                   最低分,
                    AVG(score)                                                                   平均分,
                    SUM(CASE WHEN score >= 60 THEN 1 ELSE 0 END) / COUNT(*) * 100                及格率,
                    SUM(CASE WHEN score >= 70 AND score < 80 THEN 1 ELSE 0 END) / COUNT(*) * 100 中等率,
                    SUM(CASE WHEN score >= 80 AND score < 90 THEN 1 ELSE 0 END) / COUNT(*) * 100 优良率,
                    SUM(CASE WHEN score >= 90 THEN 1 ELSE 0 END) / COUNT(*) * 100                优秀率
             FROM SC
             GROUP BY C) A ON Course.C = A.ID
ORDER BY 选修人数 DESC,ID ASC;

# 15. 按各科成绩进行排序，并显示排名， Score 重复时保留名次空缺

SELECT score,
       CASE
         WHEN @prevRank = score THEN ''
         WHEN @prevRank := score THEN @curRank := @curRank + 1
         END AS 排名
FROM SC,
     (SELECT @curRank := 0,@prevRank := null) B
ORDER BY score DESC;


# 15.1 按各科成绩进行排序，并显示排名， Score 重复时合并名次

SELECT score,
       CASE
         WHEN @prevRank = score THEN @curRank
         WHEN @prevRank := score THEN @curRank := @curRank + 1
         END AS 排名
FROM SC,
     (SELECT @curRank := 0,@prevRank := null) B
ORDER BY score DESC;


# 16.  查询学生的总成绩，并进行排名，总分重复时保留名次空缺

SELECT S,
       sum,
       CASE
         WHEN @prevRank = sum THEN ''
         WHEN @prevRanK := sum Then @curRank := @curRank + 1
         END AS PM
FROM (SELECT S,SUM(score) sum
      FROM SC
      GROUP BY S) A,
     (SELECT @prevRank := NULL,@curRank := 0) B
ORDER BY sum DESC;


# 16.1 查询学生的总成绩，并进行排名，总分重复时不保留名次空

SELECT S,
       sum,
       CASE
         WHEN @prevRank = sum THEN @curRank
         WHEN @prevRanK := sum THEN @curRank := @curRank + 1
         END AS PM
FROM (SELECT S,SUM(score) sum
      FROM SC
      GROUP BY S) A,
     (SELECT @prevRank := NULL,@curRank := 0) B
ORDER BY sum DESC;


# 17. 统计各科成绩各分数段人数：课程编号，课程名称，[100-85]，[85-70]，[70-60]，[60-0] 及所占百分

SELECT *
FROM Course
       JOIN
     (SELECT C                                                                             课程编号,
             SUM(CASE WHEN score < 100 AND score >= 85 THEN 1 ELSE 0 END)                  '[100-85]人数',
             SUM(CASE WHEN score >= 70 THEN 1 ELSE 0 END)                                  '[85-70]人数',
             SUM(CASE WHEN score >= 60 THEN 1 ELSE 0 END)                                  '[70-60]人数',
             SUM(CASE WHEN score THEN 1 ELSE 0 END)                                        '[60-0]人数',
             SUM(CASE WHEN score < 100 AND score >= 85 THEN 1 ELSE 0 END) / COUNT(*) * 100 '[100-85]百分比',
             SUM(CASE WHEN score >= 70 THEN 1 ELSE 0 END) / COUNT(*) * 100                 '[85-70]百分比',
             SUM(CASE WHEN score >= 60 THEN 1 ELSE 0 END) / COUNT(*) * 100                 '[70-60]百分比',
             SUM(CASE WHEN score THEN 1 ELSE 0 END) / COUNT(*) * 100                       '[60-0]百分比'
      FROM SC
      GROUP BY C) b ON Course.C = b.课程编号;


# 18. 查询各科成绩前三名的记录

SELECT a.S,a.C,a.score
FROM SC a
       LEFT JOIN SC b ON a.C = b.C AND a.score < b.score
GROUP BY a.S,a.C,a.score
HAVING COUNT(b.S) < 3
ORDER BY a.C,a.score DESC;

SELECT *
FROM SC a
WHERE (SELECT COUNT(DISTINCT score) FROM SC WHERE C = a.C AND score >= a.score) <= 3
ORDER BY a.C,a.score DESC;

# 19. 查询每门课程被选修的学生数 

SELECT c, COUNT(*)
FROM SC
GROUP BY SC.C;


# 20. 查询出只选修两门课程的学生学号和姓名 

SELECT Student.Sname,Student.S
FROM Student
WHERE (SELECT COUNT(*)
       FROM SC
       WHERE Student.S = SC.S
       GROUP BY SC.S) = 2;


# 21. 查询男生、女生人数

SELECT Ssex,COUNT(*)
FROM Student
GROUP BY Ssex;


# 22. 查询名字中含有「风」字的学生信息

SELECT *
FROM Student
WHERE Sname LIKE '%风%';


# 23. 查询同名同性学生名单，并统计同名人数

SELECT Sname,Ssex,COUNT(*) 同名人数
FROM Student
GROUP BY Student.Sname,Ssex
HAVING COUNT(*) > 1;


# 24. 查询 1990 年出生的学生名单

SELECT *
FROM Student
WHERE YEAR(Sage) > 1990;


# 25. 查询每门课程的平均成绩，结果按平均成绩降序排列，平均成绩相同时，按课程编号升序排列

SELECT C, AVG(SC.score) AVG
FROM SC
GROUP BY SC.C
ORDER BY AVG DESC,C ASC;


# 26. 查询平均成绩大于等于 85 的所有学生的学号、姓名和平均成绩 

SELECT Student.*,B.AVG
FROM Student
       JOIN (SELECT S,AVG(score) AVG
             FROM SC
             GROUP BY SC.S
             HAVING AVG >= 85) B ON Student.S = B.S;


# 27. 查询课程名称为「数学」，且分数低于 60 的学生姓名和分数 

SELECT Student.*,B.score
FROM Student
       JOIN (SELECT *
             FROM SC
             WHERE EXISTS(SELECT *
                          FROM Course
                          WHERE SC.C = Course.C
                            AND Cname = '数学')
               AND score < 60) B ON Student.S = B.S;


# 28. 查询所有学生的课程及分数情况（存在学生没成绩，没选课的情况）

SELECT *
FROM Student
       LEFT JOIN SC ON Student.S = SC.S;


# 29. 查询任何一门课程成绩在 70 分以上的姓名、课程名称和分数

SELECT Student.Sname,Course.Cname,B.score
FROM Student
       JOIN (SELECT *
             FROM SC
             WHERE SC.score > 70) B ON Student.S = B.S
       JOIN Course ON B.C = Course.C;


# 30. 查询不及格的课程

SELECT *
FROM Course
WHERE EXISTS(SELECT *
             FROM SC
             WHERE Course.C = SC.C
               AND score < 60);


# 31. 查询课程编号为 01 且课程成绩在 80 分以上的学生的学号和姓名

SELECT *
FROM Student
WHERE EXISTS(SELECT *
             FROM SC
             WHERE Student.S = SC.S
               AND C = '01'
               AND score = 80);


# 32. 求每门课程的学生人数 

SELECT C,COUNT(*)
FROM SC
GROUP BY C;


# 33. 成绩不重复，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩

SELECT Student.*, B.score
FROM Student
       JOIN (SELECT *
             FROM SC
             WHERE EXISTS(
                       SELECT *
                       FROM Course
                       WHERE SC.C = Course.C
                         AND EXISTS(SELECT *
                                    FROM Teacher
                                    WHERE Course.T = Teacher.T
                                      AND Tname = '张三')
                     )
             ORDER BY score DESC
             LIMIT 1) B ON Student.S = B.S;


# 34. 成绩有重复的情况下，查询选修「张三」老师所授课程的学生中，成绩最高的学生信息及其成绩

SELECT *
FROM SC a
WHERE EXISTS(
    SELECT *
    FROM Course
    WHERE a.C = Course.C
      AND EXISTS(SELECT *
                 FROM Teacher
                 WHERE Course.T = Teacher.T
                   AND Tname = '李四')
  )
  AND (SELECT COUNT(DISTINCT score) FROM SC WHERE C = a.C AND score > a.score) < 1
ORDER BY a.C,a.score DESC;


# 35. 查询不同课程成绩相同的学生的学生编号、课程编号、学生成绩 

SELECT *
FROM SC A
   , SC B
WHERE A.score = B.score
  AND A.C != B.C
  AND A.S != B.S;


# 36. 查询每门功成绩最好的前两名

SELECT *
FROM SC A
WHERE (SELECT COUNT(DISTINCT B.score)
       FROM SC B
       WHERE A.C = B.C
         AND B.score > A.score) < 2;


# 37. 统计每门课程的学生选修人数（超过 5 人的课程才统计）。

SELECT C
FROM SC
GROUP BY C
HAVING COUNT(*) > 5;


# 38. 检索至少选修两门课程的学生学号 

SELECT S
FROM SC
GROUP BY S
HAVING COUNT(*) >= 2;


# 39. 查询选修了全部课程的学生信息

SELECT *
FROM Student
WHERE EXISTS(SELECT S
             FROM SC
             WHERE SC.S = Student.S
             GROUP BY S
             HAVING COUNT(*) = (SELECT COUNT(*) FROM Course));

SELECT *
FROM Student a
WHERE NOT EXISTS
  (SELECT *
   FROM SC b
   WHERE S = '01'
     AND NOT EXISTS
     (SELECT * FROM SC c WHERE c.S = a.S AND c.C = b.C));


# 40. 查询各学生的年龄，只按年份来算 

SELECT (YEAR(NOW()) - YEAR(Sage)) AGE
FROM Student;

# 41. 按照出生日期来算，当前月日 < 出生年月的月日则，年龄减一

SELECT if(DAY(NOW()) > DAY(Sage) AND MONTH(NOW()) > MONTH(Sage), (YEAR(NOW()) - YEAR(Sage)) - 1,
          (YEAR(NOW()) - YEAR(Sage)))
FROM Student,
     (SELECT @AGE := 0) B;


# 42. 查询本周过生日的学生

SELECT Student.*
FROM Student
WHERE WEEK(Sage) = WEEK(NOW());


# 43. 查询下周过生日的学生

SELECT Student.*
FROM Student
WHERE WEEK(Sage) = WEEK(NOW()) + 1;


# 44. 查询本月过生日的学生

SELECT *
FROM Student
WHERE MONTH(Student.Sage) = MONTH(NOW());


# 45. 查询下月过生日的学生

SELECT *
FROM Student
WHERE MONTH(Student.Sage) = MONTH(NOW()) + 1;

本文参与腾讯云自媒体同步曝光计划，分享自作者个人站点/博客。

原始发表：2019年02月22日，如有侵权请联系 cloudcommunity@tencent.com 删除

sql

本文分享自作者个人站点/博客前往查看

如有侵权，请联系 cloudcommunity@tencent.com 删除。

本文参与腾讯云自媒体同步曝光计划，欢迎热爱写作的你一起参与！

sql

登录后参与评论

0 条评论

热度

SQL题目50道持续更新

SQL题目50道持续更新

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

SQL题目50道 持续更新

SQL题目50道 持续更新

社区

活动

资源

关于

腾讯云开发者

热门产品

热门推荐

更多推荐

SQL题目50道持续更新

SQL题目50道持续更新