首页
学习
活动
专区
圈层
工具
发布
社区首页 >专栏 >Leetcode 303. Range Sum Query - Immutable

Leetcode 303. Range Sum Query - Immutable

作者头像
Tyan
发布2019-05-25 22:16:17
发布2019-05-25 22:16:17
4160
举报
文章被收录于专栏:SnailTyanSnailTyan

版权声明:博客文章都是作者辛苦整理的,转载请注明出处,谢谢! https://cloud.tencent.com/developer/article/1433619

文章作者:Tyan

博客:noahsnail.com | CSDN | 简书

1. Description

2. Solution

  • Version 1
代码语言:javascript
复制
class NumArray {
public:
    NumArray(vector<int> nums) {
        this->nums = nums;
    }
    
    int sumRange(int i, int j) {
        int sum = 0;
        for(int index = i; index <= j; index++) {
            sum += nums[index];
        }
        return sum;
    }

private:
    vector<int> nums;
};

/**
 * Your NumArray object will be instantiated and called as such:
 * NumArray obj = new NumArray(nums);
 * int param_1 = obj.sumRange(i,j);
 */
  • Version 2
代码语言:javascript
复制
class NumArray {
public:
    NumArray(vector<int> nums) {
        int sum = 0;
        for(int num: nums) {
            sum += num;
            sums.push_back(sum);
        }
    }
    
    int sumRange(int i, int j) {
        if(i > 0) {
            return sums[j] - sums[i - 1];
        }
        return sums[j];
    }

private:
    vector<int> sums;
};

/**
 * Your NumArray object will be instantiated and called as such:
 * NumArray obj = new NumArray(nums);
 * int param_1 = obj.sumRange(i,j);
 */

Reference

  1. https://leetcode.com/problems/range-sum-query-immutable/description/
本文参与 腾讯云自媒体同步曝光计划,分享自作者个人站点/博客。
原始发表:2019年02月18日,如有侵权请联系 cloudcommunity@tencent.com 删除

本文分享自 作者个人站点/博客 前往查看

如有侵权,请联系 cloudcommunity@tencent.com 删除。

本文参与 腾讯云自媒体同步曝光计划  ,欢迎热爱写作的你一起参与!

评论
登录后参与评论
0 条评论
热度
最新
推荐阅读
目录
  • 1. Description
  • 2. Solution
  • Reference
领券
问题归档专栏文章快讯文章归档关键词归档开发者手册归档开发者手册 Section 归档