Leetcode 242. Valid Anagram

Tyan

发布于 2019-05-25 22:55:59

3360

发布于 2019-05-25 22:55:59

文章被收录于专栏：SnailTyanSnailTyan

文章作者：Tyan

博客：noahsnail.com | CSDN | 简书

1. Description

2. Solution

Version 1

class Solution {
public:
    bool isAnagram(string s, string t) {
        sort(s.begin(), s.end());
        sort(t.begin(), t.end());
        return s == t;
    }
};

Version 2

class Solution {
public:
    bool isAnagram(string s, string t) {
        if(s.size() != t.size()) {
            return false;
        }
        map<char, int> m;
        for(int i = 0; i < s.size(); i++) {
            m[s[i]]++;
            
        }
        for(int i = 0; i < t.size(); i++) {
            m[t[i]]--;
            if(m[t[i]] < 0) {
                return false;
            }
        }
        for(auto iter : m) {
            if(iter.second != 0) {
                return false;
            }
        }
        return true;
    }
};

Version 3

class Solution {
public:
    bool isAnagram(string s, string t) {
        if(s.size() != t.size()) {
            return false;
        }
        vector<int> alpha(26);
        for(char ch : s) {
            alpha[ch - 'a']++;
        }
        for(char ch : t) {
            alpha[ch - 'a']--;
        }
        for(int x : alpha) {
            if(x != 0) {
                return false;
            }
        }
        return true;
    }
};