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社区首页 >专栏 >Leetcode 23. Merge k Sorted Lists

Leetcode 23. Merge k Sorted Lists

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Tyan
发布2019-05-25 22:58:13
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发布2019-05-25 22:58:13
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文章被收录于专栏:SnailTyanSnailTyan

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文章作者:Tyan

博客:noahsnail.com | CSDN | 简书

1. Description

2. Solution

  • Version 1
代码语言:javascript
复制
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* mergeKLists(vector<ListNode*>& lists) {
        int size = lists.size();
        if(size == 0) {
            return NULL;
        }
        ListNode* result = lists[0];
        for(int i = 1; i < size; i++) {
            result = mergeTwoLists(result, lists[i]);
        }
        return result;
    }

private:
    ListNode* mergeTwoLists(ListNode* first, ListNode* second) {
        ListNode* ptrFirst = first;
        ListNode* ptrSecond = second;
        ListNode* head = new ListNode(0);
        ListNode* current = head;
        while(ptrFirst && ptrSecond) {
            if(ptrFirst->val > ptrSecond->val) {
                current->next = ptrSecond;
                ptrSecond = ptrSecond->next;
            }
            else {
                current->next = ptrFirst;
                ptrFirst = ptrFirst->next;
            }
            current = current->next;
        }
        if(ptrFirst) {
            current->next = ptrFirst;
        }
        if(ptrSecond) {
            current->next = ptrSecond;
        }
        return head->next;
    }

};
  • Version 2
代码语言:javascript
复制
/**
 * Definition for singly-linked list.
 * struct ListNode {
 *     int val;
 *     ListNode *next;
 *     ListNode(int x) : val(x), next(NULL) {}
 * };
 */
class Solution {
public:
    ListNode* mergeKLists(vector<ListNode*>& lists) {
        int size = lists.size();
        if(size == 0) {
            return NULL;
        }
        ListNode* result = NULL;
        while(lists.size() != 1) {
            ListNode * l1 = lists.back();
            lists.pop_back();
            ListNode * l2 = lists.back();
            lists.pop_back();
            result = mergeTwoLists(l1, l2);
            lists.insert(lists.begin(), result);
        }
        return lists[0];
    }

private:
    ListNode* mergeTwoLists(ListNode* first, ListNode* second) {
        ListNode* ptrFirst = first;
        ListNode* ptrSecond = second;
        ListNode* head = new ListNode(0);
        ListNode* current = head;
        while(ptrFirst && ptrSecond) {
            if(ptrFirst->val > ptrSecond->val) {
                current->next = ptrSecond;
                ptrSecond = ptrSecond->next;
            }
            else {
                current->next = ptrFirst;
                ptrFirst = ptrFirst->next;
            }
            current = current->next;
        }
        if(ptrFirst) {
            current->next = ptrFirst;
        }
        if(ptrSecond) {
            current->next = ptrSecond;
        }
        return head->next;
    }

};

Reference

  1. https://leetcode.com/problems/merge-k-sorted-lists/description/
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  • 1. Description
  • 2. Solution
  • Reference
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