Leetcode 599. Minimum Index Sum of Two Lists

Tyan

发布于 2019-05-25 23:26:25

2850

发布于 2019-05-25 23:26:25

文章被收录于专栏：SnailTyan

文章作者：Tyan

博客：noahsnail.com | CSDN | 简书

1. Description

2. Solution

class Solution {
public:
    vector<string> findRestaurant(vector<string>& list1, vector<string>& list2) {
        int min = INT_MAX;
        vector<string> result;
        unordered_map<string, int> m;
        for(int i = 0; i < list1.size(); i++) {
            m[list1[i]] = i;
        }
        for(int i = 0; i < list2.size(); i++) {
            if(m.find(list2[i]) != m.end()) {
                int index = m[list2[i]] + i;
                if(index < min) {
                    min = m[list2[i]] + i;
                    result.clear();
                    result.emplace_back(list2[i]);
                }
                else if(index == min) {
                    result.emplace_back(list2[i]);
                }
            }
        }
        return result;
    }
};