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社区首页 >专栏 >POJ 刷题系列:2299. Ultra-QuickSort

POJ 刷题系列:2299. Ultra-QuickSort

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发布2019-05-26 07:51:20
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发布2019-05-26 07:51:20
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文章被收录于专栏:机器学习入门机器学习入门

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://cloud.tencent.com/developer/article/1434484

POJ 刷题系列:2299. Ultra-QuickSort

传送门:2299. Ultra-QuickSort

题意:

给出长度为n的序列,每次只能交换相邻的两个元素,问至少要交换几次才使得该序列为递增序列。

思路:

实际上是让你求解逆序对的个数,求逆序对的个数可以采用归并排序。曾写过一篇关于算法细节系列(27):时间复杂度为何还能优化?今天又重新复习了一遍,有了一些新的理解。除了分治能够把解决问题的深度限定在logn\log n内之外,此处还有一个优化的关键,当给定了两个子数组a,b时,因为a和b均已排好序,此时在数组b中找出比数组a小的元素,可以采用【统一加】的原则,比如数组a中有元素:

代码语言:javascript
复制
a = [3, 4, 5, 6]
b = [1, 2, 3, 4]

对于数组a中的3而言,b中存在1和2,所以count += 2
此时,对于数组a中的4而言,b中存在1,2和3,count += 3
因为1,2对于a中的3而言一定是逆序对,那么对于a中的4更是如此,所以我们完全可以设置一个全局指针j,在上一轮的基础上继续比较,详见代码。

代码如下:

代码语言:javascript
复制
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.Map;
import java.util.StringTokenizer;

public class Main{

    String INPUT = "./data/judge/201801/P2299.txt";

    public static void main(String[] args) throws IOException {
        new Main().run();
    }

    int N;
    long count;
    long[] num;

    void merge(int s, int e) {
        if (e - s <= 1) return;
        int m = (s + e) / 2;
        merge(s, m);
        merge(m, e);
        for (int i = s, j = m; i < m; ++i) {
            while (j < e && num[i] > num[j]) j ++;
            count += j - m;
        }

        mergeSort(s, e);
    }

    void mergeSort(int s, int e) {
        int m = (s + e) / 2;
        long[] aux = new long[e - s];
        int i = s;
        int j = m;
        int k = 0;

        while (i < m && j < e) {
            if (num[i] < num[j]) aux[k++] = num[i++];
            else aux[k++] = num[j++];
        }

        while (i < m) aux[k++] = num[i++];
        while (j < e) aux[k++] = num[j++];

        for (int t = 0, l = s; l < e; ++l) num[l] = aux[t++];
    }

    void read() {
        while (true) {
            N = ni();
            if (N == 0) break;

            num = new long[N];
            for (int i = 0; i < N; ++i) {
                num[i] = ni();
            }

            count = 0;
            merge(0, N);
            out.println(count);
        }
    }

    FastScanner in;
    PrintWriter out;

    void run() throws IOException {
        boolean oj;
        try {
            oj = ! System.getProperty("user.dir").equals("F:\\oxygen_workspace\\Algorithm");
        } catch (Exception e) {
            oj = System.getProperty("ONLINE_JUDGE") != null;
        }

        InputStream is = oj ? System.in : new FileInputStream(new File(INPUT));
        in = new FastScanner(is);
        out = new PrintWriter(System.out);
        long s = System.currentTimeMillis();
        read();
        out.flush();
        if (!oj){
            System.out.println("[" + (System.currentTimeMillis() - s) + "ms]");
        }
    }

    public boolean more(){
        return in.hasNext();
    }

    public int ni(){
        return in.nextInt();
    }

    public long nl(){
        return in.nextLong();
    }

    public double nd(){
        return in.nextDouble();
    }

    public String ns(){
        return in.nextString();
    }

    public char nc(){
        return in.nextChar();
    }

    class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        boolean hasNext;

        public FastScanner(InputStream is) throws IOException {
            br = new BufferedReader(new InputStreamReader(is));
            hasNext = true;
        }

        public String nextToken() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e) {
                    hasNext = false;
                    return "##";
                }
            }
            return st.nextToken();
        }

        String next = null;
        public boolean hasNext(){
            next = nextToken();
            return hasNext;
        }

        public int nextInt() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Integer.parseInt(more);
        }

        public long nextLong() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Long.parseLong(more);
        }

        public double nextDouble() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Double.parseDouble(more);
        }

        public String nextString(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more;
        }

        public char nextChar(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more.charAt(0);
        }
    }

    static class D{

        public static void pp(int[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }

        public static void pp(char[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }
    }

    static class ArrayUtils {

        public static void fill(int[][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                Arrays.fill(f[i], value);
            }
        }

        public static void fill(int[][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }

        public static void fill(int[][][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }
    }

    static class Num{
        public static <K> void inc(Map<K, Integer> mem, K k) {
            if (!mem.containsKey(k)) mem.put(k, 0);
            mem.put(k, mem.get(k) + 1);
        }
    }
}
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原始发表:2018年01月14日,如有侵权请联系 cloudcommunity@tencent.com 删除

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