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社区首页 >专栏 >POJ 刷题系列:1789. Truck History

POJ 刷题系列:1789. Truck History

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用户1147447
发布2019-05-26 09:17:51
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发布2019-05-26 09:17:51
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文章被收录于专栏:机器学习入门机器学习入门

版权声明:本文为博主原创文章,未经博主允许不得转载。 https://cloud.tencent.com/developer/article/1434588

POJ 刷题系列:1789. Truck History

传送门:1789. Truck History

题意:

用一个7位的string代表一个编号,两个编号之间的distance代表这两个编号之间不同字母的个数。一个编号只能由另一个编号“衍生”出来,代价是这两个编号之间相应的distance,现在要找出一个“衍生”方案,使得总代价最小,也就是distance之和最小。 例如有如下4个编号: aaaaaaa baaaaaa abaaaaa aabaaaa 显然的,第二,第三和第四编号分别从第一编号衍生出来的代价最小,因为第二,第三和第四编号分别与第一编号只有一个字母是不同的,相应的distance都是1,加起来是3。也就是最小代价为3。

思路:

裸的prim算法,起初用PriorityQueue来实现,发现MLE了,因为记录了太多重复的顶点。重新看了《挑战》,这才发现prim算法的魅力,它用了一个mincost数组记录从集合x出发到每个顶点的最小值,这样一来就避免了重复顶点问题,其次由于贪心,即使集合x在慢慢壮大,也能保证程序的准确性。

代码如下:

代码语言:javascript
复制
import java.io.BufferedReader;
import java.io.File;
import java.io.FileInputStream;
import java.io.IOException;
import java.io.InputStream;
import java.io.InputStreamReader;
import java.io.PrintWriter;
import java.util.Arrays;
import java.util.HashSet;
import java.util.Map;
import java.util.PriorityQueue;
import java.util.Queue;
import java.util.Set;
import java.util.StringTokenizer;

public class Main{

    String INPUT = "./data/judge/201712/P1789.txt";

    public static void main(String[] args) throws IOException {
        new Main().run();
    }

    static final int INF = 0x3f3f3f3f;

    int dist(String a, String b) {
        int n = 7;
        int sum = 0;
        char[] ca = a.toCharArray();
        char[] cb = b.toCharArray();
        for (int i = 0; i < n; ++i) {
            sum += ca[i] != cb[i] ? 1 : 0;
        }
        return sum;
    }

    class Node implements Comparable<Node>{
        int v;
        int dist;
        Node(int v, int dist){
            this.v = v;
            this.dist = dist;
        }

        @Override
        public int compareTo(Node o) {
            return this.dist - o.dist;
        }

        @Override
        public String toString() {
            return "(" + v + ", " + dist + ")";
        }
    }

    void read() {
        while (true) {
            int n = ni();
            if (n == 0) break;
            String[] ns = new String[n];
            for (int i = 0; i < n; ++i) {
                ns[i] = ns();
            }

            int[][] graph = new int[n][n];
            for (int i = 0; i < n; ++i) {
                Arrays.fill(graph[i], INF);
            }

            for (int i = 0; i < n; ++i) {
                for (int j = i + 1; j < n; ++j) {
                    graph[i][j] = graph[j][i] = dist(ns[i], ns[j]);
                }
            }

            int[] mincost = new int[n];
            Arrays.fill(mincost, INF);
            boolean[] used = new boolean[n];
            mincost[0] = 0; // 从0出发能够找到距离0的边为1

            int sum = 0;
            while (true) {
                int v = -1; // 下一个顶点
                for (int u = 0; u < n; ++u) {
                    if (!used[u] && (v == -1 || mincost[u] < mincost[v])) v = u;
                }

                if (v == -1) break;
                sum += mincost[v];
                used[v] = true;
                for (int u = 0; u < n; ++u) {
                    mincost[u] = Math.min(mincost[u], graph[v][u]);
                }
            }

            out.println("The highest possible quality is " + "1/" + sum + ".");
        }
    }

    FastScanner in;
    PrintWriter out;

    void run() throws IOException {
        boolean oj;
        try {
            oj = ! System.getProperty("user.dir").equals("F:\\oxygen_workspace\\Algorithm");
        } catch (Exception e) {
            oj = System.getProperty("ONLINE_JUDGE") != null;
        }

        InputStream is = oj ? System.in : new FileInputStream(new File(INPUT));
        in = new FastScanner(is);
        out = new PrintWriter(System.out);
        long s = System.currentTimeMillis();
        read();
        out.flush();
        if (!oj){
            System.out.println("[" + (System.currentTimeMillis() - s) + "ms]");
        }
    }

    public boolean more(){
        return in.hasNext();
    }

    public int ni(){
        return in.nextInt();
    }

    public long nl(){
        return in.nextLong();
    }

    public double nd(){
        return in.nextDouble();
    }

    public String ns(){
        return in.nextString();
    }

    public char nc(){
        return in.nextChar();
    }

    class FastScanner {
        BufferedReader br;
        StringTokenizer st;
        boolean hasNext;

        public FastScanner(InputStream is) throws IOException {
            br = new BufferedReader(new InputStreamReader(is));
            hasNext = true;
        }

        public String nextToken() {
            while (st == null || !st.hasMoreTokens()) {
                try {
                    st = new StringTokenizer(br.readLine());
                } catch (Exception e) {
                    hasNext = false;
                    return "##";
                }
            }
            return st.nextToken();
        }

        String next = null;
        public boolean hasNext(){
            next = nextToken();
            return hasNext;
        }

        public int nextInt() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Integer.parseInt(more);
        }

        public long nextLong() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Long.parseLong(more);
        }

        public double nextDouble() {
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return Double.parseDouble(more);
        }

        public String nextString(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more;
        }

        public char nextChar(){
            if (next == null){
                hasNext();
            }
            String more = next;
            next = null;
            return more.charAt(0);
        }
    }

    static class D{

        public static void pp(int[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }

        public static void pp(char[][] board, int row, int col) {
            StringBuilder sb = new StringBuilder();
            for (int i = 0; i < row; ++i) {
                for (int j = 0; j < col; ++j) {
                    sb.append(board[i][j] + (j + 1 == col ? "\n" : " "));
                }
            }
            System.out.println(sb.toString());
        }
    }

    static class ArrayUtils {

        public static void fill(int[][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                Arrays.fill(f[i], value);
            }
        }

        public static void fill(int[][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }

        public static void fill(int[][][][] f, int value) {
            for (int i = 0; i < f.length; ++i) {
                fill(f[i], value);
            }
        }
    }

    static class Num{
        public static <K> void inc(Map<K, Integer> mem, K k) {
            if (!mem.containsKey(k)) mem.put(k, 0);
            mem.put(k, mem.get(k) + 1);
        }
    }
}
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原始发表:2017年12月28日,如有侵权请联系 cloudcommunity@tencent.com 删除

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