假设数组为 :
12345
如果左移一次即为:23451 ,依次类推
如果右移一次即为:51234 ,依次类推
翻转则为:54321
我们来实现下这个程序:
1#include <stdio.h>
2#include <stdlib.h>
3#include <string.h>
4#define NR(x) (sizeof(x)/sizeof(x[0]))
5//数组左移
6int buffer_left_move(int *buffer , int buf_len)
7{
8 int i ;
9 char tmp = buffer[0];
10 for(i = 1 ; i < buf_len ; i++)
11 {
12 buffer[i-1] = buffer[i] ;
13 }
14 buffer[buf_len-1] = tmp ;
15}
16//数组右移
17int buffer_right_move(int *buffer , int buf_len)
18{
19 int i ;
20 char tmp = buffer[buf_len - 1];
21 for(i = buf_len ; i > 0 ; i--)
22 {
23 buffer[i] = buffer[i-1] ;
24 }
25 buffer[0] = tmp ;
26}
27//数组翻转
28int buffer_turn_over(int *buffer , int buf_len)
29{
30 int size = buf_len ;
31 int i , tmp;
32 for(i = 0 ; i < size/2 ; i++)
33 {
34 tmp = buffer[i] ;
35 buffer[i] = buffer[size-1-i] ;
36 buffer[size-1-i] = tmp;
37 }
38}
39//打印数组
40void print_buffer(int *buffer, int buf_len)
41{
42 int i ;
43 system("cls");
44 printf("please input \'a' or \'b' or \'w' \n");
45 for(i = 0 ; i < buf_len ; i++)
46 {
47 printf("%d",buffer[i]);
48 }
49 putchar('\n');
50}
51
52int main(void)
53{
54 int buffer[5] = {1,2,3,4,5} ;
55
56 print_buffer(buffer,NR(buffer));
57 while(1)
58 {
59 switch(getch())
60 {
61 //左边
62 case 'a':
63 buffer_left_move(buffer,NR(buffer)) ;
64 print_buffer(buffer,5);
65 break ;
66 //右边
67 case 'd':
68 buffer_right_move(buffer,NR(buffer));
69 print_buffer(buffer,5);
70 break ;
71 //翻转
72 case 'w':
73 buffer_turn_over(buffer,NR(buffer)) ;
74 print_buffer(buffer,5);
75 break ;
76 }
77 }
78 return 0 ;
79}
运行结果:
按下a为不断左移,按下d为不断右移,按下w则为翻转