【leetcode系列】26. 删除排序数组中的重复项

// nums is passed in by reference. (i.e., without making a copy)
int len = removeDuplicates(nums);

// any modification to nums in your function would be known by the caller.
// using the length returned by your function, it prints the first len elements.
for (int i = 0; i < len; i++) {
    print(nums[i]);
}

/*
 * @lc app=leetcode id=26 lang=javascript
 *
 * [26] Remove Duplicates from Sorted Array
 *
 * https://leetcode.com/problems/remove-duplicates-from-sorted-array/description/
 *
 * algorithms
 * Easy (39.76%)
 * Total Accepted:    539.7K
 * Total Submissions: 1.4M
 * Testcase Example:  '[1,1,2]'
 *
 * Given a sorted array nums, remove the duplicates in-place such that each
 * element appear only once and return the new length.
 *
 * Do not allocate extra space for another array, you must do this by modifying
 * the input array in-place with O(1) extra memory.
 *
 * Example 1:
 *
 *
 * Given nums = [1,1,2],
 *
 * Your function should return length = 2, with the first two elements of nums
 * being 1 and 2 respectively.
 *
 * It doesn't matter what you leave beyond the returned length.
 *
 * Example 2:
 *
 *
 * Given nums = [0,0,1,1,1,2,2,3,3,4],
 *
 * Your function should return length = 5, with the first five elements of nums
 * being modified to 0, 1, 2, 3, and 4 respectively.
 *
 * It doesn't matter what values are set beyond the returned length.
 *
 *
 * Clarification:
 *
 * Confused why the returned value is an integer but your answer is an array?
 *
 * Note that the input array is passed in by reference, which means
 * modification to the input array will be known to the caller as well.
 *
 * Internally you can think of this:
 *
 *
 * // nums is passed in by reference. (i.e., without making a copy)
 * int len = removeDuplicates(nums);
 *
 * // any modification to nums in your function would be known by the caller.
 * // using the length returned by your function, it prints the first len
 * elements.
 * for (int i = 0; i < len; i++) {
 * print(nums[i]);
 * }
 *
 */
/**
 * @param {number[]} nums
 * @return {number}
 */
var removeDuplicates = function(nums) {
    const size = nums.length;
    let slowP = 0;
    for (let fastP = 0; fastP < size; fastP++) {
        if (nums[fastP] !== nums[slowP]) {
            slowP++;
            nums[slowP] = nums[fastP]
        }   
    }
    return slowP + 1;
};