A + B

one + two =
three four + five six =
zero seven + eight nine =
zero + zero =

#include<bits/stdc++.h>
using namespace std;
map<string,int> mp;
int main(){
	mp["zero"]=0;mp["one"]=1;mp["two"]=2;mp["three"]=3;mp["four"]=4;mp["five"]=5;mp["six"]=6;mp["seven"]=7;mp["eight"]=8;mp["nine"]=9;
	char a[20];
	int sum=0,sum1=0;//用sum表示每次输入的数字，sum1能暂时储存‘+’前面的数。
	while(~scanf("%s",a)){
		if(a[0]=='+') {
			sum1 = sum;
			sum =0;
		}
		if(mp.count(a)) sum = sum*10+mp[a];  //map的用法，有这个元素返回1，无则返回0；
		if(a[0]=='='){
			if(sum1+sum==0) break;
			else
			 printf("%d\n",sum1+sum);
			 sum = sum1 =0;
		}
	}
	return 0;
}