Python 实现敏感目录扫描的示例代码

砸漏

发布于 2020-11-02 15:19:29

1.1K0

发布于 2020-11-02 15:19:29

文章被收录于专栏：恩蓝脚本

01 实现背景

1、PHPdict.txt，一个文本文件，包含可能的敏感目录后缀

2、HackRequests模块，安全测试人员专用的类Requests模块

02 实现目标

利用HackRequests模块，配合敏感目录字典PHPdict.txt，实现一个简单的敏感目录扫描Python文件

03 注意事项

1、输入URL时要输全：如 https://www.baidu.com/、 https://www.csdn.net/

2、为防止网站可能存在的简单反爬机制，我们简单添加headers信息，尝试绕过反爬

04 实现代码

import HackRequests
def HR(url):
 h = HackRequests.hackRequests()
 header = {
 "Connection": "keep-alive",
 "User-Agent":"Mozilla/5.0 (Windows NT 10.0; Win64; x64; rv:73.0) Gecko/20100101 Firefox/73.0"
 }
 try:
 u = h.http(url=url,headers=header)
 if u.status_code == 200:
  print("%s is success!" %url)
 else:
  print("%s is failed! %d" %(url,u.status_code))
 except:
 pass
with open("C:\Users\Dell\Desktop\Python\PHPdict.txt","r") as file:
 lines = file.readlines()
 urls = []
 url_begin = input('请输入你要扫描的网站：')
 for line in lines:
 url = f'{url_begin}{line}'
 urls.append(url)

for url in urls:
 print(url)
 HR(url)

05 实现效果