python标记编码 字符串转换成数字_Python：将字母数字字符串可逆编码为整数

参考链接： Python的字符串Strings decode

I want to convert a string (composed of alphanumeric characters) into an integer and then convert this integer back into a string:

 string --> int --> string

 In other words, I want to represent an alphanumeric string by an integer.

 I found a working solution, which I included in the answer, but I do not think it is the best solution, and I am interested in other ideas/methods.

 Please don't tag this as duplicate just because a lot of similar questions already exist, I specifically want an easy way of transforming a string into an integer and vice versa.

 This should work for strings that contain alphanumeric characters, i.e. strings containing numbers and letters.

 解决方案

 Here's what I have so far:

 string --> bytes

 mBytes = m.encode("utf-8")

 bytes --> int

 mInt = int.from_bytes(mBytes, byteorder="big")

 int --> bytes

 mBytes = mInt.to_bytes(((mInt.bit_length() + 7) // 8), byteorder="big")

 bytes --> string

 m = mBytes.decode("utf-8")

 try it out:

 m = "test123"

 mBytes = m.encode("utf-8")

 mInt = int.from_bytes(mBytes, byteorder="big")

 mBytes2 = mInt.to_bytes(((mInt.bit_length() + 7) // 8), byteorder="big")

 m2 = mBytes2.decode("utf-8")

 print(m == m2)

 Here is an identical reusable version of the above:

 class BytesIntEncoder:

 @staticmethod

 def encode(b: bytes) -> int:

 return int.from_bytes(b, byteorder='big')

 @staticmethod

 def decode(i: int) -> bytes:

 return i.to_bytes(((i.bit_length() + 7) // 8), byteorder='big')

 If you're using Python <3.6, remove the optional type annotations.

 Test:

 >>> s = 'Test123'

 >>> b = s.encode()

 >>> b

 b'Test123'

 >>> BytesIntEncoder.encode(b)

 23755444588720691

 >>> BytesIntEncoder.decode(_)

 b'Test123'

 >>> _.decode()

 'Test123'