表: UserActivity
+---------------+---------+
| Column Name | Type |
+---------------+---------+
| username | varchar |
| activity | varchar |
| startDate | Date |
| endDate | Date |
+---------------+---------+
该表不包含主键
该表包含每个用户在一段时间内进行的活动的信息
名为 username 的用户在 startDate 到 endDate 日内有一次活动
写一条SQL查询展示每一位用户 最近第二次 的活动(倒数第二次)
如果用户仅有一次活动,返回该活动
一个用户不能同时进行超过一项活动,以 任意 顺序返回结果
下面是查询结果格式的例子:
UserActivity 表:
+------------+--------------+-------------+-------------+
| username | activity | startDate | endDate |
+------------+--------------+-------------+-------------+
| Alice | Travel | 2020-02-12 | 2020-02-20 |
| Alice | Dancing | 2020-02-21 | 2020-02-23 |
| Alice | Travel | 2020-02-24 | 2020-02-28 |
| Bob | Travel | 2020-02-11 | 2020-02-18 |
+------------+--------------+-------------+-------------+
Result 表:
+------------+--------------+-------------+-------------+
| username | activity | startDate | endDate |
+------------+--------------+-------------+-------------+
| Alice | Dancing | 2020-02-21 | 2020-02-23 |
| Bob | Travel | 2020-02-11 | 2020-02-18 |
+------------+--------------+-------------+-------------+
Alice 最近第二次的活动是从 2020-02-24 到 2020-02-28 的旅行,
在此之前的 2020-02-21 到 2020-02-23 她进行了舞蹈
Bob 只有一条记录,我们就取这条记录
来源:力扣(LeetCode) 链接:https://leetcode-cn.com/problems/get-the-second-most-recent-activity 著作权归领扣网络所有。商业转载请联系官方授权,非商业转载请注明出处。
select *
from UserActivity
group by username
having count(*)=1
{"headers": ["username", "activity", "startDate", "endDate"],
"values": [["Bob", "Travel", "2020-02-11", "2020-02-18"]]}
select username, activity, startDate, endDate
from
(
select *, rank() over(partition by username order by startDate desc) rnk
from UserActivity
) t
where rnk = 2
{"headers": ["username", "activity", "startDate", "endDate"],
"values": [["Alice", "Dancing", "2020-02-21", "2020-02-23"]]}
# Write your MySQL query statement below
select *
from
(
select *
from UserActivity
group by username
having count(*)=1
union all
select username, activity, startDate, endDate
from
(
select *, rank() over(partition by username order by startDate desc) rnk
from UserActivity
) t
where rnk = 2
) t
更简洁的写法
# Write your MySQL query statement below
select username, activity, startDate, endDate
from
(
select *,
rank() over (partition by username order by startDate desc) rnk,
count(*) over (partition by username) cnt
from UserActivity
) t
where cnt = 1 or rnk = 2