Two elements of a binary search tree (BST) are swapped by mistake.
Recover the tree without changing its structure.
Note: A solution using O(n) space is pretty straight forward. Could you devise a constant space solution?
/**
* Definition for a binary tree node.
* struct TreeNode {
* int val;
* TreeNode *left;
* TreeNode *right;
* TreeNode(int x) : val(x), left(NULL), right(NULL) {}
* };
*/
class Solution {
private:
TreeNode* pre = new TreeNode(INT_MIN);
TreeNode* first = NULL;
TreeNode* second = NULL;
void searchTree(TreeNode* root) {
if(!root)
return ;
searchTree(root->left);
if(!first && pre->val >= root->val)
first = pre;
if(first && pre->val >= root->val)
second = root;
pre = root;
searchTree(root->right);
}
public:
void recoverTree(TreeNode* root) {
searchTree(root);
swap(first->val, second->val);
}
};