MySQL :only_full_group_by解决方案

# 车主表
create table owner
(
    id         int(10) auto_increment
        primary key,
    owner_name varchar(10) null,
    brand_id   int(10)     null
);

# 车辆表
create table vehicle
(
    id       int(10) auto_increment
        primary key,
    brand_id int(10) null
);

# 车辆品牌表
create table brand
(
    id         int(10) auto_increment
        primary key,
    brand_name varchar(10) null
);


INSERT INTO `halodb`.`owner` (`id`, `owner_name`, `brand_id`) VALUES (1, 'debug', 1);
INSERT INTO `halodb`.`owner` (`id`, `owner_name`, `brand_id`) VALUES (2, 'Ltx', 2);
INSERT INTO `halodb`.`owner` (`id`, `owner_name`, `brand_id`) VALUES (3, 'Ltx', 1);

INSERT INTO `halodb`.`brand` (`id`, `brand_name`) VALUES (1, '比亚迪');
INSERT INTO `halodb`.`brand` (`id`, `brand_name`) VALUES (2, '大众');

INSERT INTO `halodb`.`vehicle` (`id`, `brand_id`) VALUES (1, 1);
INSERT INTO `halodb`.`vehicle` (`id`, `brand_id`) VALUES (2, 2);
INSERT INTO `halodb`.`vehicle` (`id`, `brand_id`) VALUES (3, 1);

select v.id as vehicleId,
       b.id as brandId, b.brand_name as brandName,
       o.owner_name as ownerName
from vehicle v
         left join brand b on v.brand_id = b.id
         left join owner o on b.id = o.brand_id

select v.id as vehicleId,
       b.id as brandId, b.brand_name as brandName,
       o.owner_name as ownerName
from vehicle v
         left join brand b on v.brand_id = b.id
         left join owner o on b.id = o.brand_id
group by vehicleId;

select brand_name from brand group by brand_name;