java验证电话号码的正则_java使用正则表达式判断电话号码

大家好，又见面了，我是你们的朋友全栈君。

I want to have phone number in working combination of ‘0’ followed by 10 digit mobile number (or) 0091 folllowed by 10 digit mobile number (or) +91 followed by 10 digit number.

1) 0 followed and +91 folowed numbers are working with following regex i also want 0091 followed number to be worked, my regex is:

“^([0]|(?:[0][0]|\\+)(91))([7-9]{1})([0-9]{9})$”;

Could you suggest me working a regex.

解决方案

The exact regex you seem to be going for (based on what you’ve tried so far) is:

^(?:0091|\\+91|0)[7-9][0-9]{9}$

Begins with 0, +91 or 0091

Followed by a 7-9

Followed by exactly 9 numbers

No capture groups

Must match entire input

As a general tip, to have worked this out yourself I’d advise using a site like RegExr or RegexPal

Set it to multi-line mode (so that ^ and $ match at the end of each line) then add 0091, +91 and 0 into the input box on separate lines – so you have something like this.

Then try to make a regex that matches just that part, in your case you needed something like

^0091|\+91|0$

Note: on RegExr you don’t have to escape backslashes (so when you use the regex in java you need to go through escaping them).

版权声明：本文内容由互联网用户自发贡献，该文观点仅代表作者本人。本站仅提供信息存储空间服务，不拥有所有权，不承担相关法律责任。如发现本站有涉嫌侵权/违法违规的内容， 请发送邮件至 举报，一经查实，本站将立刻删除。

发布者：全栈程序员栈长，转载请注明出处：https://javaforall.cn/192596.html原文链接：https://javaforall.cn