blocks|key|1281370|text|为此，您可以使用带有%5E\"%7C\"$模式的String#replaceAll()。|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1281371|例如。|1281372|string+=+string.replaceAll("%5E\"%7C\"$",+"");|code-block|syntax|javascript|1281373|要了解有关正则表达式的更多信息，请参阅http://regular-expression.info。|1281374|也就是说，这看起来有点像您正在尝试发明一个CSV解析器。如果是这样的话，我建议四处寻找现有的库，比如OpenCSV。|1281375|entityMap|0|LINK|mutability|MUTABLE|url|http://java.sun.com/javase/6/docs/api/java/lang/String.html#replaceAll%2528java.lang.String,%2520java.lang.String%2529|1|http://regular-expression.info/|2|http://opencsv.sourceforge.net/^0|A|7|K|J|K|J|0|0|0|0|J|U|1|0|1E|7|2|0^^$0|@$1|2|3|4|5|6|7|12|8|@$9|13|A|14|B|C]|$9|15|A|16|B|C]]|D|@$9|17|A|18|1|19]]|E|$]]|$1|F|3|G|5|6|7|1A|8|@]|D|@]|E|$]]|$1|H|3|I|5|J|7|1B|8|@]|D|@]|E|$K|L]]|$1|M|3|N|5|6|7|1C|8|@]|D|@$9|1D|A|1E|1|1F]]|E|$]]|$1|O|3|P|5|6|7|1G|8|@]|D|@$9|1H|A|1I|1|1J]]|E|$]]|$1|Q|3|-4|5|6|7|1K|8|@]|D|@]|E|$]]]|R|$S|$5|T|U|V|E|$W|X]]|Y|$5|T|U|V|E|$W|Z]]|10|$5|T|U|V|E|$W|11]]]]

You can use <a href="http://java.sun.com/javase/6/docs/api/java/lang/String.html#replaceAll%28java.lang.String,%20java.lang.String%29" rel="noreferrer"><code>String#replaceAll()</code></a> with a pattern of <code>^\"|\"$</code> for this.

E.g.

<pre><code>string = string.replaceAll("^\"|\"$", "");
</code></pre>

To learn more about regular expressions, have al ook at <a href="http://regular-expression.info" rel="noreferrer">http://regular-expression.info</a>.

That said, this smells a bit like that you're trying to invent a CSV parser. If so, I'd suggest to look around for existing libraries, such as <a href="http://opencsv.sourceforge.net/" rel="noreferrer">OpenCSV</a>.

blocks|key|1066693|text|要删除字符串中的第一个字符和最后一个字符，请使用：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1066694|myString+=+myString.substring(1,+myString.length()-1);|code-block|syntax|javascript|1066695|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

To remove the first character and last character from the string, use:

<pre><code>myString = myString.substring(1, myString.length()-1);
</code></pre>

blocks|key|1066866|text|如果双引号只存在于开头和结尾，一个简单的代码就可以很好地工作：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1066867|string+=+string.replace("\"",+"");|offset|length|style|CODE|1066868|entityMap^0|0|0|Y|0^^$0|@$1|2|3|4|5|6|7|J|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|K|8|@$D|L|E|M|F|G]]|9|@]|A|$]]|$1|H|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|I|$]]

If the double quotes only exist at the beginning and the end, a simple code as this would work perfectly:

<code>string = string.replace("\"", "");</code>

blocks|key|1281657|text|这是我发现的最好的方法，从字符串的开头和结尾去掉双引号。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1281658|someString.replace+(/(%5E")%7C("$)/g,+'')|code-block|syntax|javascript|1281659|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

This is the best way I found, to strip double quotes from the beginning and end of a string.

<pre><code>someString.replace (/(^")|("$)/g, '')
</code></pre>

blocks|key|1281618|text|首先，我们检查字符串是否有双引号，如果是，则删除它们。如果你知道条件句是双引号的，你可以跳过它。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1281619|if+(string.length()+>=+2+&&+string.charAt(0)+==+'"'+&&+string.charAt(string.length()+-+1)+==+'"')
{
++++string+=+string.substring(1,+string.length()+-+1);
}|code-block|syntax|javascript|1281620|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

First, we check to see if the String is doubled quoted, and if so, remove them. You can skip the conditional if in fact you know it's double quoted.

<pre><code>if (string.length() &gt;= 2 &amp;&amp; string.charAt(0) == '"' &amp;&amp; string.charAt(string.length() - 1) == '"')
{
 string = string.substring(1, string.length() - 1);
}
</code></pre>

blocks|key|1281469|text|使用Guava，您可以编写更优雅的CharMatcher.is('\"').trimFrom(mystring);|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1281470|entityMap^0|H|14|0^^$0|@$1|2|3|4|5|6|7|H|8|@$9|I|A|J|B|C]]|D|@]|E|$]]|$1|F|3|-4|5|6|7|K|8|@]|D|@]|E|$]]]|G|$]]

Using Guava you can write more elegantly <code>CharMatcher.is('\"').trimFrom(mystring);</code>

blocks|key|1066957|text|编辑:我刚刚意识到，我应该指定只有在两者都存在的情况下才能工作。否则，该字符串不会被认为是带引号的。在处理CSV文件时，这样的场景就出现在我面前。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1066958|org.apache.commons.lang3.StringUtils.unwrap("\"abc\"",+"\"")++++=+"abc"
org.apache.commons.lang3.StringUtils.unwrap("\"abc",+"\"")++++=+"\"abc"
org.apache.commons.lang3.StringUtils.unwrap("abc\"",+"\"")++++=+"abc\""|code-block|syntax|javascript|1066959|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Edited: Just realized that I should specify that this works only if both of them exists. Otherwise the string is not considered quoted. Such scenario appeared for me when working with CSV files.

<pre><code>org.apache.commons.lang3.StringUtils.unwrap("\"abc\"", "\"") = "abc"
org.apache.commons.lang3.StringUtils.unwrap("\"abc", "\"") = "\"abc"
org.apache.commons.lang3.StringUtils.unwrap("abc\"", "\"") = "abc\""
</code></pre>

blocks|key|1281661|text|当与java.util.regex.Matcher一起使用时，下面的模式将匹配双引号之间的任何字符串，而不会影响字符串中出现的双引号：|type|unstyled|depth|inlineStyleRanges|offset|length|style|CODE|entityRanges|data|1281662|"[%5E\"][\\p{Print}]*[%5E\"]"|code-block|syntax|javascript|1281663|entityMap^0|2|N|0|0^^$0|@$1|2|3|4|5|6|7|M|8|@$9|N|A|O|B|C]]|D|@]|E|$]]|$1|F|3|G|5|H|7|P|8|@]|D|@]|E|$I|J]]|$1|K|3|-4|5|6|7|Q|8|@]|D|@]|E|$]]]|L|$]]

The pattern below, when used with <code>java.util.regex.Matcher</code>, will match any string between double quotes without affecting occurrences of double quotes inside the string:

<pre><code>"[^\"][\\p{Print}]*[^\"]"
</code></pre>

blocks|key|1281578|text|Matcher+m+=+Pattern.compile("%5E\"(.*)\"$").matcher(value);
String+strUnquoted+=+value;
if+(m.find())+{
++++strUnquoted+=+m.group(1);
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1281579|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>Matcher m = Pattern.compile("^\"(.*)\"$").matcher(value);
String strUnquoted = value;
if (m.find()) {
 strUnquoted = m.group(1);
}
</code></pre>

blocks|key|1281705|text|稍微修改一下@brcolow的答案|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1281706|if+(string+!=+null+&&+string.length()+>=+2+&&+string.startsWith("\"")+&&+string.endsWith("\"")+{
++++string+=+string.substring(1,+string.length()+-+1);
}|code-block|syntax|javascript|1281707|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

Modifying @brcolow's answer a bit

<pre><code>if (string != null &amp;&amp; string.length() &gt;= 2 &amp;&amp; string.startsWith("\"") &amp;&amp; string.endsWith("\"") {
 string = string.substring(1, string.length() - 1);
}
</code></pre>

blocks|key|1067004|text|我使用的是这样简单的东西：|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1067005|if(str.startsWith("\"")+&&+str.endsWith("\""))
++++++++{
++++++++++++str+=+str.substring(1,+str.length()-1);
++++++++}|code-block|syntax|javascript|1067006|entityMap^0|0|0^^$0|@$1|2|3|4|5|6|7|I|8|@]|9|@]|A|$]]|$1|B|3|C|5|D|7|J|8|@]|9|@]|A|$E|F]]|$1|G|3|-4|5|6|7|K|8|@]|9|@]|A|$]]]|H|$]]

I am using something as simple as this :
<pre><code>if(str.startsWith(&quot;\&quot;&quot;) &amp;&amp; str.endsWith(&quot;\&quot;&quot;))
 {
 str = str.substring(1, str.length()-1);
 }
</code></pre>

blocks|key|1067025|text|public+String+removeDoubleQuotes(String+request)+{
++++return+request.replace("\"",+"");
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1067026|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>public String removeDoubleQuotes(String request) {
 return request.replace(&quot;\&quot;&quot;, &quot;&quot;);
}
</code></pre>

blocks|key|1281587|text|private+static+String+removeQuotesFromStartAndEndOfString(String+inputStr)+{
++++String+result+=+inputStr;
++++int+firstQuote+=+inputStr.indexOf('\"');
++++int+lastQuote+=+result.lastIndexOf('\"');
++++int+strLength+=+inputStr.length();
++++if+(firstQuote+==+0+&&+lastQuote+==+strLength+-+1)+{
++++++++result+=+result.substring(1,+strLength+-+1);
++++}
++++return+result;
}|type|code-block|depth|inlineStyleRanges|entityRanges|data|syntax|javascript|1281588|unstyled|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|G|8|@]|9|@]|A|$B|C]]|$1|D|3|-4|5|E|7|H|8|@]|9|@]|A|$]]]|F|$]]

<pre><code>private static String removeQuotesFromStartAndEndOfString(String inputStr) {
 String result = inputStr;
 int firstQuote = inputStr.indexOf('\"');
 int lastQuote = result.lastIndexOf('\"');
 int strLength = inputStr.length();
 if (firstQuote == 0 &amp;&amp; lastQuote == strLength - 1) {
 result = result.substring(1, strLength - 1);
 }
 return result;
}
</code></pre>

blocks|key|1281338|text|找到每个双引号的索引，并在其中插入一个空字符串。|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1281339|entityMap^0|0^^$0|@$1|2|3|4|5|6|7|D|8|@]|9|@]|A|$]]|$1|B|3|-4|5|6|7|E|8|@]|9|@]|A|$]]]|C|$]]

find indexes of each double quotes and insert an empty string there.

blocks|key|1281823|text|Groovy|type|unstyled|depth|inlineStyleRanges|entityRanges|data|1281824|您可以在groovy中使用正则表达式从字符串中减去一个子字符串：|1281825|String+unquotedString+=+theString+-+~/%5E"/+-+~/"$/|code-block|syntax|javascript|1281826|entityMap^0|0|0|0^^$0|@$1|2|3|4|5|6|7|K|8|@]|9|@]|A|$]]|$1|B|3|C|5|6|7|L|8|@]|9|@]|A|$]]|$1|D|3|E|5|F|7|M|8|@]|9|@]|A|$G|H]]|$1|I|3|-4|5|6|7|N|8|@]|9|@]|A|$]]]|J|$]]

<h2>Groovy</h2>
You can subtract a substring from a string using a regular expression in groovy:
<pre><code>String unquotedString = theString - ~/^&quot;/ - ~/&quot;$/
</code></pre>

I would like to trim a beginning and ending double quote (") from a string. 
How can I achieve that in Java? Thanks!

How can I trim beginning and ending double quotes from a string?

我想从字符串中去掉开头和结尾的双引号(")。我如何在Java中实现这一点呢？谢谢!

问如何裁剪字符串的开头和结尾的双引号？
EN

回答 15

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问如何裁剪字符串的开头和结尾的双引号？EN

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问如何裁剪字符串的开头和结尾的双引号？
EN